anonymous
  • anonymous
how do i simplify a radical expression that has a variable in it?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\sqrt[3]{x^7}\]
amistre64
  • amistre64
make it a rational exponent :)
anonymous
  • anonymous
\[x^{7/3}\]

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More answers

amistre64
  • amistre64
x^(7/3) = x^(6/3 + 1/3) x^2 cbrt(x)
anonymous
  • anonymous
it needs to be simplified not solved
amistre64
  • amistre64
that is simplified; in order to 'solve' we would have said x = some number
amistre64
  • amistre64
to simplify just means to write it in another way
amistre64
  • amistre64
cbrt(x^7) = x^2 cbrt(x)
anonymous
  • anonymous
ok thanks but all the answers have either a 3 and an x or a 2 and a 3 and an x
amistre64
  • amistre64
maybe it more accurate to write it like this: cbrt(x^7) <=> x^2 cbrt(x) :)
amistre64
  • amistre64
\[\sqrt[3]{x^7} <=> x^2 \sqrt[3]{x}\]
anonymous
  • anonymous
thank you so much
amistre64
  • amistre64
yw :)
anonymous
  • anonymous
\[\frac4{9-\sqrt6}\]
anonymous
  • anonymous
rationalize the denimonator
amistre64
  • amistre64
you gotta multiply by the conjugate; which is just cahngeing that - into a +
amistre64
  • amistre64
4 (9+sqrt(6)) 4(9+sqrt(6)) ----------- = ----------- 81 -6 75
amistre64
  • amistre64
multiply top AND bottom by the conjugate ;)
anonymous
  • anonymous
thx
amistre64
  • amistre64
yw :) if you post a new question in the question box, more people will get a chance to help and you wont run the risk of me not seeing it in this post :)
anonymous
  • anonymous
\[\log_{5}75-\log_{5}3 \]
anonymous
  • anonymous
write the expression as a single logarithm whose coefficient is 1?
amistre64
  • amistre64
log(a) - log(b) = log(a/b) so, log5(75) - log(3) = log5(75/3) = log5(25)
anonymous
  • anonymous
\[\sqrt{9x+22}=x \]
amistre64
  • amistre64
^2 both sides to get: 9x +22 = x^2 0 = x^2 -9x +22 0 = (x-11)(x+2) x = 11 and -2 ; but we gotta dbl check because this way can have fake results: sqrt(9(11)+22) ?= 11 sqrt(99+22) ?= 11 sqrt(121) ?= 11 11 = 11 ; that ones good -------------------------------- sqrt(9(-2) +22) = -2 .... aint no way that one works lol x = 11 is the answer
anonymous
  • anonymous
u r a math god!!
amistre64
  • amistre64
more of a math demigod lol
anonymous
  • anonymous
lol
amistre64
  • amistre64
my indian name is "runs with scissors" ....
anonymous
  • anonymous
\[\log_{9}25 \]
anonymous
  • anonymous
calculator keeps giving me the wrong answer
amistre64
  • amistre64
change of base it.... is my guess
amistre64
  • amistre64
ln(25) ----- = answer ln(9)
amistre64
  • amistre64
1.464.... maybe?
anonymous
  • anonymous
thanks that worked
amistre64
  • amistre64
it should :)
amistre64
  • amistre64
spose we have 9^x = 25 log(9^x) = log(25) x log(9) = log(25) x = log(25)/log(9) x = log9(25) its all good

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