anonymous
  • anonymous
Soybean meal is 16% protien, cornmeal is 8% protien. How many pounds of each should be mixed together in order to get 320-lb mixture that is 14% protien?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
i could have sworn i just did this problem. matter of fact i am sure of it.
anonymous
  • anonymous
good then you can tell me how to solve it lol
anonymous
  • anonymous
be happy to write it again in you missed it.

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anonymous
  • anonymous
sure. in english or equation? or both?
anonymous
  • anonymous
equation so I can see how it is solved
anonymous
  • anonymous
ok you want to end up with 14% of 320=44.8 pounds of protein. 16% will come from soybeans so if we call x the amount of soybeans you will get .16 x the rest will come from cornmeal and since you will have 320 pounds total if you have 0 amount of soybeans you will have 320 - x amount of cornmeal, 8 % of which is \[.08\times(320-x)\]
anonymous
  • anonymous
so you get the equation \[.16x+.08(320-x)=.14\times 320=44.8\]
anonymous
  • anonymous
now we solve for x: \[.16x+.08(320-x)=44.8\] \[.16x+25.6-.08x=44.8\] \[.08x+25.6=44.8\] \[.08x=44.8-25.6=19.2\] \[x=\frac{19.2}{.08}=240\]
anonymous
  • anonymous
and of course that makes the amount of cornmeal 80
anonymous
  • anonymous
so it would be 44.8 ponds of soybean and 19.2 pounds of cornmeal is that right?
anonymous
  • anonymous
oh no
anonymous
  • anonymous
solving for x gives x = 240
anonymous
  • anonymous
240 pounds of soybeans and therefore 80 pounds of cornmeal
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
clear or no?
anonymous
  • anonymous
yes clearer now
anonymous
  • anonymous
k

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