anonymous
  • anonymous
25xto the 3rd degreey to 2degree +125xto 2 degreeyto5degree FACTOR COMPLETELY
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[(25x^3)^2+(125x^2)^5\]?
anonymous
  • anonymous
HOW DO YOU ENTER EXPONENTS ON THE KEYBOARD
anonymous
  • anonymous
i think you have a symol palette where it says \[\sum\]equation

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anonymous
  • anonymous
i am writing latex to do it
anonymous
  • anonymous
i would start by writing \[(5^2x^3)^2+(5^3x^2)^5\]
anonymous
  • anonymous
if this is the problem.
anonymous
  • anonymous
if it is not let me know and i will not continue with this method
anonymous
  • anonymous
NO WHEN I PUT TO WHATEVER DEGREE THAT IS THE EXPONENT
anonymous
  • anonymous
25XTO 3 DEGREE Y TO 2 DEGREE + 125X TO 2 DEGREE Y TO 5 DEGREE
anonymous
  • anonymous
\[25(x^3)^2+125(x^2)^5\]?
anonymous
  • anonymous
YOU LEFT OUT HE Y'S AND THEIR DEGREES AND NO BRACKETS OR PARENTHESES
anonymous
  • anonymous
oho
anonymous
  • anonymous
\[25x^3y^2+125x^2y^5\]
anonymous
  • anonymous
YES
anonymous
  • anonymous
ok each has a common factor of \[25x^2y^2\] is that clear?
anonymous
  • anonymous
so you can factor it out and write \[25x^2y^2(x+5y^3\]
anonymous
  • anonymous
NO, I NEED STEP BY STEP
anonymous
  • anonymous
ok. you have two numbers 25 and 125
anonymous
  • anonymous
YES
anonymous
  • anonymous
their greatest common factor is 25 because \[25=25\times 1\] and \[125=25\times 5\] so that is going to come out of the parenthese
anonymous
  • anonymous
just looking at that part we can say that \[25+125=25(1+5)\]
anonymous
  • anonymous
THERE IS NO PARENTHESES
anonymous
  • anonymous
no there are not. but "factoring" means to write as a produce. that is our job, to put the parenthese in
anonymous
  • anonymous
OK
anonymous
  • anonymous
so now for the variables: first term has \[x^3\] second term has \[x^2\]
anonymous
  • anonymous
their greatest common factor is \[x^2\] because \[x^2=x^2\times 1\] and \[x^3=x^2\times x\]
anonymous
  • anonymous
I AM SORRY BUT THIS ISN'T HELPING
anonymous
  • anonymous
so we are going to "factor out" a 25 and an \[x^2\]
anonymous
  • anonymous
i have a better idea.
anonymous
  • anonymous
look at my answer which is \[25x^2y^2(x+5y^3)\] multiply out using the distributive law and see if you get what you started with.
anonymous
  • anonymous
maybe then it will be clear where the \[25x^2y^2\] came from, and why we pulled it out front of the parentheses

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