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anonymous
 5 years ago
25xto the 3rd degreey to 2degree +125xto 2 degreeyto5degree
FACTOR COMPLETELY
anonymous
 5 years ago
25xto the 3rd degreey to 2degree +125xto 2 degreeyto5degree FACTOR COMPLETELY

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(25x^3)^2+(125x^2)^5\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0HOW DO YOU ENTER EXPONENTS ON THE KEYBOARD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think you have a symol palette where it says \[\sum\]equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am writing latex to do it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i would start by writing \[(5^2x^3)^2+(5^3x^2)^5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if this is the problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if it is not let me know and i will not continue with this method

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0NO WHEN I PUT TO WHATEVER DEGREE THAT IS THE EXPONENT

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.025XTO 3 DEGREE Y TO 2 DEGREE + 125X TO 2 DEGREE Y TO 5 DEGREE

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[25(x^3)^2+125(x^2)^5\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0YOU LEFT OUT HE Y'S AND THEIR DEGREES AND NO BRACKETS OR PARENTHESES

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[25x^3y^2+125x^2y^5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok each has a common factor of \[25x^2y^2\] is that clear?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you can factor it out and write \[25x^2y^2(x+5y^3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0NO, I NEED STEP BY STEP

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. you have two numbers 25 and 125

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0their greatest common factor is 25 because \[25=25\times 1\] and \[125=25\times 5\] so that is going to come out of the parenthese

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just looking at that part we can say that \[25+125=25(1+5)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THERE IS NO PARENTHESES

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no there are not. but "factoring" means to write as a produce. that is our job, to put the parenthese in

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so now for the variables: first term has \[x^3\] second term has \[x^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0their greatest common factor is \[x^2\] because \[x^2=x^2\times 1\] and \[x^3=x^2\times x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I AM SORRY BUT THIS ISN'T HELPING

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we are going to "factor out" a 25 and an \[x^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have a better idea.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0look at my answer which is \[25x^2y^2(x+5y^3)\] multiply out using the distributive law and see if you get what you started with.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0maybe then it will be clear where the \[25x^2y^2\] came from, and why we pulled it out front of the parentheses
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