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anonymous

  • 5 years ago

check for symmetry, y=(x)/(x^2+1) I think thats how you set it up...

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  1. anonymous
    • 5 years ago
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    check that this is odd. \[\frac{odd}{even}=odd\] for functions

  2. anonymous
    • 5 years ago
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    Im so confused...

  3. anonymous
    • 5 years ago
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    ok it is symmetric with respect to the origin.

  4. anonymous
    • 5 years ago
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    we can check first with numbers and then with variables.

  5. anonymous
    • 5 years ago
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    let x = 1, \[y=\frac{1}{1^2+1}=\frac{1}{2}\]

  6. anonymous
    • 5 years ago
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    now let x = -1 \[y=\frac{-1}{(-1)^2+1}=\frac{-1}{1+1}=-\frac{1}{2}\]

  7. anonymous
    • 5 years ago
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    this says go right 1, up one half, left one, down one half.

  8. anonymous
    • 5 years ago
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    since we have \[(1,\frac{1}{2})\] and also \[(-1,-\frac{1}{2})\]

  9. anonymous
    • 5 years ago
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    Oh! I see now! Ok, one more... xy^2+10=0, what do you do with the 10?

  10. anonymous
    • 5 years ago
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    are you sure? we should check with variables as well. x = a, get \[y=\frac{a}{a^2+1}\] x = -a get \[y=-\frac{a}{a^2+1}\]

  11. anonymous
    • 5 years ago
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    so symmetric wrt the origin.

  12. anonymous
    • 5 years ago
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    yeah i get it. the x=1 thing helped

  13. anonymous
    • 5 years ago
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    \[xy^2+10=0\] \[xy^2=-10\] \[x=-\frac{10}{y^2}\]

  14. anonymous
    • 5 years ago
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    ahhhh thank you!

  15. anonymous
    • 5 years ago
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    numbers always help

  16. anonymous
    • 5 years ago
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    system is weird ignore last remark.

  17. anonymous
    • 5 years ago
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    Well thank you very much, helps a lot1

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spraguer (Moderator)
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