anonymous
  • anonymous
check for symmetry, y=(x)/(x^2+1) I think thats how you set it up...
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
check that this is odd. \[\frac{odd}{even}=odd\] for functions
anonymous
  • anonymous
Im so confused...
anonymous
  • anonymous
ok it is symmetric with respect to the origin.

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anonymous
  • anonymous
we can check first with numbers and then with variables.
anonymous
  • anonymous
let x = 1, \[y=\frac{1}{1^2+1}=\frac{1}{2}\]
anonymous
  • anonymous
now let x = -1 \[y=\frac{-1}{(-1)^2+1}=\frac{-1}{1+1}=-\frac{1}{2}\]
anonymous
  • anonymous
this says go right 1, up one half, left one, down one half.
anonymous
  • anonymous
since we have \[(1,\frac{1}{2})\] and also \[(-1,-\frac{1}{2})\]
anonymous
  • anonymous
Oh! I see now! Ok, one more... xy^2+10=0, what do you do with the 10?
anonymous
  • anonymous
are you sure? we should check with variables as well. x = a, get \[y=\frac{a}{a^2+1}\] x = -a get \[y=-\frac{a}{a^2+1}\]
anonymous
  • anonymous
so symmetric wrt the origin.
anonymous
  • anonymous
yeah i get it. the x=1 thing helped
anonymous
  • anonymous
\[xy^2+10=0\] \[xy^2=-10\] \[x=-\frac{10}{y^2}\]
anonymous
  • anonymous
ahhhh thank you!
anonymous
  • anonymous
numbers always help
anonymous
  • anonymous
system is weird ignore last remark.
anonymous
  • anonymous
Well thank you very much, helps a lot1

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