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anonymous

  • 5 years ago

g(x)=frac(x-3){x(x+1)}

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  1. anonymous
    • 5 years ago
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    \[g(x)=\frac{x-3}{x(x+1)}\]

  2. anonymous
    • 5 years ago
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    what is the question?

  3. anonymous
    • 5 years ago
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    yes find the vertical asymptotes if any

  4. anonymous
    • 5 years ago
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    set denominator = 0 and solve:\[x(x+1)=0\] \[x=0\] or \[x=-1\] so there are two.

  5. anonymous
    • 5 years ago
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    need the horizontal one as well? degree of numerator is 1,degree of denominator is 2, and since 2 > 1 it is \[y=0\]

  6. amistre64
    • 5 years ago
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    gotta make sure that the bottom doesnt cancel the top; if it does, that would be a hole; but this problem is good....

  7. anonymous
    • 5 years ago
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    thanks

  8. anonymous
    • 5 years ago
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    \[\log_{c}t+\log_{c}s \]

  9. amistre64
    • 5 years ago
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    logc(ts)

  10. anonymous
    • 5 years ago
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    \[log_c(ts)\]

  11. anonymous
    • 5 years ago
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    hello again.

  12. anonymous
    • 5 years ago
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    oh so the bases never changes when re-writing??

  13. amistre64
    • 5 years ago
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    not in that case :)

  14. anonymous
    • 5 years ago
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    if they are different you cannot do it.

  15. anonymous
    • 5 years ago
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    k thanks ...was always confused about that..lol teachers dont kno what they are talking about..lol

  16. anonymous
    • 5 years ago
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    typical

  17. anonymous
    • 5 years ago
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    pre-calc class?

  18. anonymous
    • 5 years ago
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    sort of its a new thing in orlando ..its a college readiness class that is basically preparing you to take pre-calc in college

  19. anonymous
    • 5 years ago
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    \[\frac{2x}5=\frac{x}3+2;solve\]

  20. toxicsugar22
    • 5 years ago
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    i amristre can u help me after her

  21. amistre64
    • 5 years ago
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    orlando eh... im over near brooksville

  22. amistre64
    • 5 years ago
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    perhaps :) hypers are easy

  23. toxicsugar22
    • 5 years ago
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    amristre can u help me after her

  24. amistre64
    • 5 years ago
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    *15 all of it.... 6x = 5x +30 x = 30 maybe?

  25. amistre64
    • 5 years ago
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    dbl check

  26. toxicsugar22
    • 5 years ago
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    amristre can u help me after

  27. amistre64
    • 5 years ago
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    60/5 = 30/3 +2 6 = 10+2 .... gonna have to see what I did lol

  28. amistre64
    • 5 years ago
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    i can yes...

  29. amistre64
    • 5 years ago
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    2x x --- = --- + 2 5 3 2x = 5x/3 +10 2x = 5x+30/3 6x = 5x +30 x = 30 ..... 2(30) 30 ---- = --- + 2 5 3 2(6) = 10 + 2 12 = 12 ; well it worked that time lol.. my dbl check must have been off

  30. amistre64
    • 5 years ago
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    60/5 = 12 lol.....

  31. anonymous
    • 5 years ago
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    answer is either -+30 or -+60..but thanks lol

  32. amistre64
    • 5 years ago
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    x = 30 fer sure

  33. anonymous
    • 5 years ago
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    ok her is my impossible problem...lol

  34. anonymous
    • 5 years ago
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    x^2+7x+10 times x^2+6x ---------- ----------- multiply x^2+8x+12 x^2+13x+40

  35. amistre64
    • 5 years ago
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    factor to see what cancels... 2,5,x,6 ------ 6,2,8,5 ,,x, --- = x/(x+8) if I see it right ,,8,

  36. anonymous
    • 5 years ago
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    brilliant!

  37. anonymous
    • 5 years ago
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    but can you walk me through it so i can no how to do it myself

  38. anonymous
    • 5 years ago
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    \[\log_{3}...x=5 \]

  39. anonymous
    • 5 years ago
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    log_{3} x=5

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