## anonymous 5 years ago I don't really know how to type this, but here it goes: log(base5) 4-log(base5) (x+3)= log(base5) 3?

1. watchmath

2. anonymous

$log_5(4)-log_5(x+3)=log_5(3)$

3. anonymous

just wanted to type it.

4. anonymous

ok fine

5. anonymous

yeah thats it

6. anonymous

$log_5(4)-log_5(3)=log_5(x+3)$ $log_5(\frac{4}{3})=log_5(x+3)$ $\frac{4}{3}=x+3$

7. anonymous

so i guess $x=-\frac{5}{3}$

8. anonymous

you switch the 3 and the (x-3?

9. anonymous

only log step was using $log(A)-log(B)=log(\frac{A}{B})$ from right to left.

10. anonymous

oh i just added $log_5(x+3)$ to both sides so it would be positive. easier that way

11. anonymous

sorry it was adding my mistake

12. anonymous

added $log_5(x+3)$ to both sides and subtracted $log_5(3)$ from both sides so i had the variable by itself on one side.

13. anonymous

clear or no?

14. anonymous

clear thanks

15. anonymous

welcome

16. anonymous