A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
I don't really know how to type this, but here it goes:
log(base5) 4log(base5) (x+3)= log(base5) 3?
anonymous
 5 years ago
I don't really know how to type this, but here it goes: log(base5) 4log(base5) (x+3)= log(base5) 3?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[log_5(4)log_5(x+3)=log_5(3)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just wanted to type it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[log_5(4)log_5(3)=log_5(x+3)\] \[log_5(\frac{4}{3})=log_5(x+3)\] \[\frac{4}{3}=x+3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i guess \[x=\frac{5}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you switch the 3 and the (x3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0only log step was using \[log(A)log(B)=log(\frac{A}{B})\] from right to left.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i just added \[log_5(x+3)\] to both sides so it would be positive. easier that way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry it was adding my mistake

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0added \[log_5(x+3)\] to both sides and subtracted \[log_5(3)\] from both sides so i had the variable by itself on one side.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you for your time.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.