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anonymous
 5 years ago
Find an expression for a cubic function f if f(3) = 108 and f(3) = f(0) = f(4) = 0.
anonymous
 5 years ago
Find an expression for a cubic function f if f(3) = 108 and f(3) = f(0) = f(4) = 0.

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1y = ax(x+3)(x4) find a by using point (3,108)

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1when you know the zeroes of a function you can po ut it in factored form say f(x) = x^24 so f(x) = (x+2)(x2) if you want to solve for 0 you get x = 2 and 2 in this case you are working backwards you know the xvalues that make f(x)=0 (x+3) =0 when x=3, f(3) =0 the x in front comes from f(0)=0 the a is a scale factor which determines the shape of graph, is it skinny or wide this is because many different graphs may have the same zeroes but only one will go through a different specific point (3,108), f(3) =108 to find the cubic equation you just need to plug in 3 for x, 108 for y and solve for a 108 = 3(3+3)(34)a 108 = (3*6*1)a 108 = 18a 108/18 = a a = 6 y = 6x(x+3)(x4) expand y=6x(x^2x12) y=6x^3 +6x^2 + 72x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks a million times

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1your welcome glad to help
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