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toxicsugar22
 5 years ago
12x^23y^2+24y84=0
give the exact coordinates of any four points on the hyperbola
toxicsugar22
 5 years ago
12x^23y^2+24y84=0 give the exact coordinates of any four points on the hyperbola

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0if x=0 3y^2 +24y 84 =0 factor out a 3 y^2 8y + 28 =0 b^2 4ac < 0, complex solutions if y=0 12x^2 = 84 x^2 = 7 x = +sqrt(7) that gives 2 points get x by itself 12x^2 = 3y^2 24y +84 x^2 = 1/4y^2  2y +7 x = sqrt[1/4y^2 2y +7] pick 2 y_values y=1 > x =+ sqrt(21/4) = +sqrt(21)/2 there are other 2 points

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.012x^2 3(y^2 +8y +____) = 84 3(___) 12x^2 3(y^2 +8y +16) = 84 3(16) 12x^2 3(y4)^2 = 84 48 = 36 12/36 x^2 3/36(y4)^2 = 1 x^2 (y4)^2    = 1 3 12

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0ok can u help me with one more

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(sqrt(3), 0) (sqrt(3),0) are 2 that i get

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that might nota worked out ....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i think i got lost trying to type it all in :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0once you have \[\frac{x^2}{3}\frac{(y4)^2}{12}=1\] cant you just pick y and solve for x?

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0lets both try that together can u please show me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0say for example \[y=2\] \[\frac{x^2}{3}\frac{4}{12}=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{x^2}{3}=1+\frac{4}{12}=1+\frac{1}{3}=\frac{4}{3}\]

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0i already gave you 4 points

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^2=4\] \[x=\pm 2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or you can pick any other y to solve for x.

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0so that is one point

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually 2: \[(2,4)\] and \[(2,4)\]

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0(+sqrt(7), 0) (+sqrt(21)/2, 1) (+2, 2) there are 6 points

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let y = 1 \[\frac{x^2}{3}\frac{(14)^2}{12}=1\] \[\frac{x^2}{3}\frac{9}{12}=1\] \[\frac{x^2}{3}=1+\frac{9}{12}=1+\frac{3}{4}=\frac{7}{4}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so \[x^2=\frac{21}{4}\] \[x=\pm \frac{\sqrt{21}}{2}\]
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