## anonymous 5 years ago (z/z^2-8z-9)+8/z+1

1. anonymous

i came up with 9z-72/(z-9)(z+1)

2. anonymous

factor the 1st denominator (z+1)(z-9) this will be the common denominator $=\frac{z+8(z-9)}{(z+1)(z-9)}$ distribute and add like terms on top 9z - 72 = 9(z-8) $=\frac{9(z-8)}{(z+1)(z-9)}$

3. anonymous

looks like you got it :)

4. anonymous

thank u

5. anonymous

$\sqrt[3]{32^{2}}$