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anonymous

  • 5 years ago

simplyfy (x-9)^3/5=8 how do you solve the power to 3/5?

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  1. watchmath
    • 5 years ago
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    Raise both sides to the 5/3 power (x-9)=8^(5/3)=32 x-9=32 x=41

  2. anonymous
    • 5 years ago
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    i dont understand still

  3. anonymous
    • 5 years ago
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    \[\sqrt[5]{(x-9)^2} = (x-9)^{3/5}\]

  4. anonymous
    • 5 years ago
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    sorry, should be \[\sqrt[5]{(x-9)^{3}}\]

  5. anonymous
    • 5 years ago
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    Now\[[\sqrt[5]{(x-9)^{3}}]^{5} = [8]^5\] \[(x-9)^3 = 8^5\] \[\sqrt[3]{(x-9)^3} = \sqrt[3]{[8^5]}\] \[x-9 = 8^{5/3}\]

  6. anonymous
    • 5 years ago
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    \[8^{5/3} = \sqrt[3]{32768} = 32\]

  7. anonymous
    • 5 years ago
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    so x-9 = 32 add 9 both sides x-9+9=32+9 x=41 hope it helps!

  8. anonymous
    • 5 years ago
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    lets try this. rather than raising to the fifth power first, take the cube root of 8 first. the cube root of 8 is 2, and 2 to the fifth power is 32. much easier that way.

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