angela210793
  • angela210793
Help me please...i want to sleep....it's 11:20pm in here....i've been looking 4 a solution for : b/a=1/3,a/c=2/3,a,b,c>0,a+b+c=34...find a=? and i still haven't found the right 1 (i guess)...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
you must be across the atlantic from me
angela210793
  • angela210793
yea...told u I'm in Albania(in north of Greece) Europe...:)
anonymous
  • anonymous
This is a tricky one. Let me try.

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More answers

angela210793
  • angela210793
sure...take ur time...i got 3*68/17...O.o
amistre64
  • amistre64
b/a=1/3 a/c=2/3 ,a,b,c>0, a+b+c=34 ; /a maybe> 1/3 + c/a = 34/a ; a/c = 2/3..so flip it 1/3 + 3/2 = 34/a 2+9 ---- = 34/a 6 11 = 204/a a = 204/11 maybe :)
anonymous
  • anonymous
I got 204/11 also.
angela210793
  • angela210793
u did? O.o (maybe it's my fault cause I'm half asleep) but i didn't get it...
angela210793
  • angela210793
let me see again
amistre64
  • amistre64
b/a = 1/3 right? a/c = 2/3 ; so c/a = 3/2 a/a + b/a + c/a = 34/a opps; left out the 1 lol
amistre64
  • amistre64
1+(1/3) + (3/2) = 34/a
anonymous
  • anonymous
correct
angela210793
  • angela210793
Ahhaaaa....now i get it....Thanks a looooooooooooooooooooot :):):)
anonymous
  • anonymous
:)

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