A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 5 years ago

Jose left the White House and drove toward the recycling plant at an average speed of 40 km/h. Rob left some time later driving in the same direction at an average speed of 48 km/h. After driving for five hours Rob caught up with Jose. How long did Jose drive before Rob caught up?

  • This Question is Closed
  1. watchmath
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Suppose Jose left y hour earlier than Rob After 5 hours here are the distance traveled by the two Jose's distance= 40y+40(5)=200+40y Rob's distance = 48(5)=240 The two distances are equal 200+40y=240 40y=40 y=1 So Jose drove 1 hour earlier. It means when Rob caught up , Jose already drove for 5+1=6 hours.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.