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angela210793

  • 5 years ago

Find this one.... {[1+(x-1)/2]/1-1/x}-x/(x-1) --------------------------- x/2 I really hope u'll get it

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  1. anonymous
    • 5 years ago
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    Thank you for the star.

  2. angela210793
    • 5 years ago
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    Uw :)...any idea abt this 1 ?

  3. anonymous
    • 5 years ago
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    Let me give it a try

  4. angela210793
    • 5 years ago
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    Thnx ^_^ :)

  5. dumbcow
    • 5 years ago
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    \[\frac{x-2}{x-1}\]

  6. angela210793
    • 5 years ago
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    @dumbcow Will you please explain me how did u get that? Please...

  7. dumbcow
    • 5 years ago
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    just do it step by step, combine fractions and use property of dividing fractions (Flip and multiply)

  8. anonymous
    • 5 years ago
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    \[\frac{((1+(x-1)/2)/1-1/x)-x/(x-1)}{\frac{x}{2}}=\frac{((-2+x) (-1+x))}{ x^2} \]

  9. angela210793
    • 5 years ago
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    thnx :)

  10. anonymous
    • 5 years ago
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    In a rush to get out a solution I did not verify the result. ie: x=17 shows that the left side and the right side are not equal. Recalculated and it appears that at first glance that the fraction is equal to one.

  11. angela210793
    • 5 years ago
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    it's ok :) I'll check it tomorrow :):):) Thnx anyway

  12. toxicsugar22
    • 5 years ago
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    dumbcow can u help me

  13. anonymous
    • 5 years ago
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    The fraction is equal to 1. The problem fraction with the braces and brackets changed to parentheses:\[\frac{((1 + (x - 1)/2)/1 - 1/x) - x/(x - 1)}{\frac{x}{2}} \]Multiply the numerator by the reciprocal of the denominator adding surrounding parentheses to the numerator.\[\frac{2}{x}(((1 + (x - 1)/2)/1 - 1/x) - x/(x - 1)) \]The following is a step by step sequence of fraction modifications, mainly simplifications to individual terms.\[\frac{2}{x}\left(((1+(x-1)/2)/1-1/x)-\frac{x}{-1+x}\right) \]\[\frac{2}{x}\left(\left(\left.\frac{1+x}{2}\right/1-1/x\right)-\frac{x}{-1+x}\right) \]\[\frac{2}{x}\left(\left(\frac{1+x}{2}/\frac{-1+x}{x}\right)-\frac{x}{-1+x}\right) \]\[\frac{2}{x}\left(\frac{x (1+x)}{2 (-1+x)}-\frac{x}{-1+x}\right) \]Multiply through by 2/x\[\left(\frac{2}{x}\right)\left(\frac{x (1+x)}{2 (-1+x)}\right)-\left(\frac{x}{-1+x}\right)\left(\frac{2}{x}\right) \]Expand the products on each side of the minus sign and simplify.\[\frac{1}{-1+x}+\frac{x}{-1+x}-\frac{2}{-1+x} \]\[\frac{1+x-2}{-1+x} \]\[\frac{-1+x}{-1+x}=1 \]

  14. angela210793
    • 5 years ago
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    Wooooow...Thanks a loooooooooooooooooooooooooooot!!!!!!!!! :) ^_^ Thanks :)

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