## angela210793 5 years ago Find this one.... {[1+(x-1)/2]/1-1/x}-x/(x-1) --------------------------- x/2 I really hope u'll get it

1. anonymous

Thank you for the star.

2. angela210793

Uw :)...any idea abt this 1 ?

3. anonymous

Let me give it a try

4. angela210793

Thnx ^_^ :)

5. anonymous

$\frac{x-2}{x-1}$

6. angela210793

@dumbcow Will you please explain me how did u get that? Please...

7. anonymous

just do it step by step, combine fractions and use property of dividing fractions (Flip and multiply)

8. anonymous

$\frac{((1+(x-1)/2)/1-1/x)-x/(x-1)}{\frac{x}{2}}=\frac{((-2+x) (-1+x))}{ x^2}$

9. angela210793

thnx :)

10. anonymous

In a rush to get out a solution I did not verify the result. ie: x=17 shows that the left side and the right side are not equal. Recalculated and it appears that at first glance that the fraction is equal to one.

11. angela210793

it's ok :) I'll check it tomorrow :):):) Thnx anyway

12. toxicsugar22

dumbcow can u help me

13. anonymous

The fraction is equal to 1. The problem fraction with the braces and brackets changed to parentheses:$\frac{((1 + (x - 1)/2)/1 - 1/x) - x/(x - 1)}{\frac{x}{2}}$Multiply the numerator by the reciprocal of the denominator adding surrounding parentheses to the numerator.$\frac{2}{x}(((1 + (x - 1)/2)/1 - 1/x) - x/(x - 1))$The following is a step by step sequence of fraction modifications, mainly simplifications to individual terms.$\frac{2}{x}\left(((1+(x-1)/2)/1-1/x)-\frac{x}{-1+x}\right)$$\frac{2}{x}\left(\left(\left.\frac{1+x}{2}\right/1-1/x\right)-\frac{x}{-1+x}\right)$$\frac{2}{x}\left(\left(\frac{1+x}{2}/\frac{-1+x}{x}\right)-\frac{x}{-1+x}\right)$$\frac{2}{x}\left(\frac{x (1+x)}{2 (-1+x)}-\frac{x}{-1+x}\right)$Multiply through by 2/x$\left(\frac{2}{x}\right)\left(\frac{x (1+x)}{2 (-1+x)}\right)-\left(\frac{x}{-1+x}\right)\left(\frac{2}{x}\right)$Expand the products on each side of the minus sign and simplify.$\frac{1}{-1+x}+\frac{x}{-1+x}-\frac{2}{-1+x}$$\frac{1+x-2}{-1+x}$$\frac{-1+x}{-1+x}=1$

14. angela210793

Wooooow...Thanks a loooooooooooooooooooooooooooot!!!!!!!!! :) ^_^ Thanks :)