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anonymous
 5 years ago
integrate 2e^(t2)x
anonymous
 5 years ago
integrate 2e^(t2)x

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1whats the variable to integrate by? x or t?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1k.... the t2 would act like a constant

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1take the 2 to the outside since its a constant

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then multiply by (t2)/(t2) and take the bottom one out since its acting like a constant as well

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and we int((t2) e^(t2)x) which = e^(t2)x bring over the constants to get: 2 e^(t2)x  (t2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why are you multiplying top and bottom by t2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2(xe ^{t2}  e ^{t2})+c\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1because I know how to int (t2) e^(t2)x; so I need to use a useful form of '1' to help me out..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(t2)/(t2) = 1 so the value of the function stays the same; only thing that changes is the way it looks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait so that "x" was "dx"?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you integrate this int (t2) e^(t2)x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and the way it looks is important to me... becasue I can int (t2) e^(t2)x :) the rest is just constants that can be dragged outside right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1t2 = say...u u e^ux ints up to e^ux

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh you have to use usub for this problem?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you can if it helps to see whats going on, but yeah....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1u sub is just a way to clean up the function to see it better; gets the distracting stuff out the way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so putting it in that form is the easiest way to solve?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1integration is not an 'easy' thing. it is an art more than a science

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1t2 = u {S} 2 e^ux dx 2 {S} e^ux dx 2 {S} (u/u) e^ux dx 2/u {S} u e^ux dx (2/u) e^ux

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you're integrating 2e^ux?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yes, but recall that i defined u = t2; and the t2 is acting like a constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah. i think i need to play around with similar problems and practice
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