A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

integrate 2e^(t-2)x

  • This Question is Closed
  1. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you sure?

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  3. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    whats the variable to integrate by? x or t?

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    dx

  5. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    k.... the t-2 would act like a constant

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (2e^(t-e)x)(1/(t-2)?

  7. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    take the 2 to the outside since its a constant

  8. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    then multiply by (t-2)/(t-2) and take the bottom one out since its acting like a constant as well

  9. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    and we int((t-2) e^(t-2)x) which = e^(t-2)x bring over the constants to get: 2 e^(t-2)x --------- (t-2)

  10. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ... +c lol

  11. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why are you multiplying top and bottom by t-2

  12. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[2(xe ^{t-2} - e ^{t-2})+c\]

  13. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    because I know how to int (t-2) e^(t-2)x; so I need to use a useful form of '1' to help me out..

  14. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    (t-2)/(t-2) = 1 so the value of the function stays the same; only thing that changes is the way it looks

  15. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wait so that "x" was "dx"?

  16. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how do you integrate this int (t-2) e^(t-2)x

  17. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    and the way it looks is important to me... becasue I can int (t-2) e^(t-2)x :) the rest is just constants that can be dragged outside right?

  18. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    integrating wrt x

  19. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    t-2 = say...u u e^ux ints up to e^ux

  20. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh you have to use u-sub for this problem?

  21. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you can if it helps to see whats going on, but yeah....

  22. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    u sub is just a way to clean up the function to see it better; gets the distracting stuff out the way

  23. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so putting it in that form is the easiest way to solve?

  24. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    integration is not an 'easy' thing. it is an art more than a science

  25. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    t-2 = u {S} 2 e^ux dx 2 {S} e^ux dx 2 {S} (u/u) e^ux dx 2/u {S} u e^ux dx (2/u) e^ux

  26. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    .... +C

  27. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so you're integrating 2e^ux?

  28. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, but recall that i defined u = t-2; and the t-2 is acting like a constant

  29. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah. i think i need to play around with similar problems and practice

  30. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks!

  31. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yw :)

  32. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.