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anonymous
 5 years ago
Use the disk or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs of the equations about each given line.
y = 6/x^2
y = 0
x = 1
x = 3
What method should I use?
anonymous
 5 years ago
Use the disk or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs of the equations about each given line. y = 6/x^2 y = 0 x = 1 x = 3 What method should I use?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've tried all of them, and I still get the wrong answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The shell method gives me 8pi, and the disk method gives me a ridiculous number

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the question seems to be asking you to do it 4 different times...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, my question uses the yaxis.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There's a list of them, and I have already done the one revolving around the xaxis

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if you wanna spin it round the y axis; shell it. 2pi 6 {S} x(1/x^2) dx ; [1,3]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes...so I thought to use the shell method first....right., that's what I did, and got 8pi

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01/x ints up to ln(x) right? so 12pi ln(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0waityou separated the 6 from the equation, and multiplied by x instead of (x + 1) or some variation of that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.012pi ln(3) should be it ; since ln(1) = 0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0constants dont get inted; they get pulled out, thats why we dont int pi and 2pi and the like

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we dont derive constants either; so why bother inting them lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sine the y axis is alreay x = 0; no need to move anything

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we don't add or subtract anything from the r(x) factor in [\int\limits_{a}^{b}r(x)h(x)dx\] if y = 0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2\pi \int\limits_{a}^{b}r(x)h(x)dx\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0nope; the radius in the shell method is as you move from 1 to 3 in this and the height is 6/x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the radius in the shell method is...? as you move from 1 to 3?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what are we spinning around?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0does the y axis the same as the x=0 axis?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0is the y axis that same as the x=0 line?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y = 0 and x = 0 look the same....oh, okay

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since y axis IS x=0; then what do we move to get this to x=0? nothing right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so r(x) = x ; h(x) = 6/x^2 r(x)h(x) = 6/x from 1 to 3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.012pi/x ints to 12pi ln(x) which means the the answer is: 12pi ln(3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer is right! i get itwhat your second to last post was. This makes sense now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks! See yah next time
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