Find the length of the graph of the curve y=(2/3)x^(1/2)+1 over the interval [0,1]

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Find the length of the graph of the curve y=(2/3)x^(1/2)+1 over the interval [0,1]

Mathematics
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well thats new lol, annoying, but new lol
the length of a curve is given by integrating sqrt(1+[f'x]^2) and can get really ugly

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Other answers:

f' = 1/6sqrt(x) in this case so we square it to get... 1/36x
36x+1 sqrt ------ to integrateif i did it right 36x
sqrt(36x+1) (x^1/2) ---------- 6
but i aint gonna do this if you aint gonna stick around for it lol

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