determine the vertical asymptotes and the end behavior of the following function. ((x^3/3)-(x^2/4)-2X-1)/((2-3x)(x+1)(2x-3))

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

determine the vertical asymptotes and the end behavior of the following function. ((x^3/3)-(x^2/4)-2X-1)/((2-3x)(x+1)(2x-3))

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

the top gets us an x^3 -------------------- the bottom gets us an x^3 so all thats left is the leading coeffs in the end.... for the ha
1/3 ---- = -1/18 as the ha if i see it right -6
nothing cancles top to bottom so the zeros in the bottom make the vas

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

2/3, -1, and 3/2
i wonder what happens when I report abuse myself lol
lol what do you mean? am i abusing you?
wait where is the -6 come from?

Not the answer you are looking for?

Search for more explanations.

Ask your own question