anonymous
  • anonymous
a rectangle garden has dimensions 25 ft by 20 ft. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 550 sq ft.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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anonymous
  • anonymous
w=22
anonymous
  • anonymous
let the horizontal dimension be 25 and the vertical be 20. then draw your path around the rectangle. There will be two ears on the left and right of area 20*w. There are two ears top and bottom area 25*w. Then there are 4 corners area w^2. In total: 40w+50w+4w^2=550 4w^2+90w=550 w=5 ft.
anonymous
  • anonymous
oh. i see thanks.

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anonymous
  • anonymous
it is just a matter of using A=l*w then substitute.
anonymous
  • anonymous
what do you mean?

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