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anonymous
 5 years ago
does anyone know what the general terms of this sequence is 3,6,10,15
anonymous
 5 years ago
does anyone know what the general terms of this sequence is 3,6,10,15

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i didnt got you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is a arithmetic sequence with a twist.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how does each sequence differs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it increase by one each time so ,2,3,4,5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know the form for an arithmetic sequence?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok ill give you the form for that and then you can try to relate it to this problem. \[\sum_{n=1}^{N}n=N*(N+1)/2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me know if that's enough to get you started

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does n represent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0n is just an integer. in the sum if you have N=3 you get 1+2+3=6= (3*4/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you these formulas for series?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it will help you find a general form for this series in terms of n where n represents with term in the series you are at.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do we alway use this formula for finding the general term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you looking for the series(sum) or sequence?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just want a quick way of figuring out the general term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0instead of keep guessing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lets break the terms into sums 1+2 1+2+3 1+2+3+4 ... so if n denotes the term we have \[\sum_{i=1}^{n+1}i=(n+1)*(n+2)/2=(n^{2}+3n+2)/2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so n=1: (1+3+2)/2=3 you can check the other terms if you want

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is there a a better way of figuring this out so you can avoid fractions in the general term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is the simplest way I know to do it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep, hope it helped a bit :)
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