Hello, I have an algebra word pro blem that I dont know how to set up so I can solve it. Can someone help me please?
Stacey Warren - Expert brainly.com
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Ok here is the word problem:
The sum of both digits, of either of two two-digit numbers, in whatever order the digits are written, is 9. The square of either of the digits of either number, minus the product of both digits, plus the square of the other digit is the number 21. The numbers are ?
a+b = 9
a^2 - ab +b^2 = 21
b = 9-a so subit in
OMG. How do I start that?
a^2 - a(9-a) +(9-a)^2 = 21
a^2 -9a +a^2 +81 +a^2 -18a = 21
3a^2 -27a +60 = 0
How are u coming up with this?
3(a^2 -9a +20) = 0
a = -(-5,-4) = 5 and 4
magic fingers lol
Well I need those fingers!
25 + 16 - 36 = 21?
i took what they gave me and determined a suitable value for b, so that i could put the whole thing in one variable and solve it for that variable