The area of an isosceles trapezoid is 90 in squared, the height is 6 inches, and the congruent legs are 10 inches. Find the length of the longer base.

- anonymous

- katieb

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- Owlfred

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- amistre64

take out the area that they give you and your left with a triangle right?

- amistre64

90 - 60 =30
we have an area of 30 to account for

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## More answers

- anonymous

I dont think im following you. How'd you get 60?

- amistre64

the height is 6 so.......
6b/2 = 30
3b = 30
b = 10 more than the other one

- amistre64

the area of a rectangle is base times height right?
6.10 = 60

- amistre64

90 total - 60 that is given = 30 left

- anonymous

But 10 is the leg not a base. So it would make triangle not a square right?

- amistre64

##### 1 Attachment

- amistre64

the longer base = 20

- amistre64

i see it lol

- anonymous

Im confused. What is 90 and how did you know that 10 was the base>>

- amistre64

then we pythag it to find the 'base'

- anonymous

see what?

- amistre64

i see that i read the problem wrong and know how to fix it...

- amistre64

6^2 + b^2 = 10^2
b^2 = 100 - 36
b = sqrt(64) = 8 , roght?

- amistre64

like this; and the problem says the trap area = 90

##### 1 Attachment

- anonymous

Hold on im working it out

- anonymous

Right i got that

- amistre64

6*16
----- = 48 for the 'area' of the triangle
2
90 - 48 = 42
6(7) = 42......
small side = 7
large side = 23 then right?

- amistre64

##### 1 Attachment

- anonymous

im working it

- anonymous

Wait I think I'm getting it but your saying 48 is the area for both the small triangles right?

- amistre64

yes;

- amistre64

together they make one triangle with a height of 6 and a base of 16

- anonymous

Oh! I got it. THanks for the help

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