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anonymous
 5 years ago
Find the area of a triangle whose sides have the measures: 6in, 9in, and 11 in.
anonymous
 5 years ago
Find the area of a triangle whose sides have the measures: 6in, 9in, and 11 in.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Heron's formula s=(1/2)(a+b+c)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im not following you. So the semipermimeter is 13 so what do you do from there?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0herons formula can be tedious; but so can the law of cosines...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.011^2 6^2 9^2  = cos(t) 2(6)(9) 9.6.sin(t)  = area 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.018sqrt(110)  = abt. 26.97 7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im lost. Law of cosines is c^2 = a^2 + b^2 2ab cos y right? And I know it can be manipulated but Im still lost

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that is the law of cosines yes; and i used it to find the angle between the legs 6 and 9 so that i could use the sin of that angle to find the area

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.06sin(t) = h 9 = base hb/2 = area

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is confusing... Im trying to work it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you make a picture? I think it would help alot.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does 6sin(t) mean?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it means 6 times the sin(angle) sin(angle) = h/6 ; so h = 6 sin(angle)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oka I got that. So how are you supposed to find t then? Can you work out the theorom because I think that's what I'm having trouble with

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i used the law of cosine and modified it to find t c^2 = a^2 + b^2 2ab cos(C) c^2 a^2b^2  = cos(C) 2ab the cosine inverse of that left side = t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but why isn't it c^2 a^2b^2+2  = cos(C)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0becasue "2ab cosC" is not addition; to solve for cosC you have to divide both sides by "2ab"
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