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ln is your clue
I know it should be shifted by 3 to the right and the answer in the back of the book shows that as a vertical asymptote (x = 3), and I know multiplying by 2 will make the function larger. I just don't understand why x = 3 becomes the vertical asymptote and not the x intercept.
Because ln is always greater than 0
ln(x) never equals 0 or less than 0
ln(x-3) is undefined at 3 and below
because you can't take ln(0) ?
you can try, but it like going to newyork to vist the grand canyon; when you get there, it aint gonna happen lol
So how could we write limit notation for the function?
lim[x->3] ln(x-3) = -inf if anything
that might have to be adjusted to say 'from the right'
This was actually a question from a graphing exercise. Trying to understand all of this so I can graph these correctly.
Thanks for the help!
Amistre, you did so well on this and that triangle problem earlier, please take a look at this one, one guy is trying to find the answer, and I have tried everything http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4dd992160ada8b0bef2a41c7