anonymous
  • anonymous
Find all asymptotes and intercepts: y = 2ln(x-3) How do I find the asymptotes and intercepts? I want to understand the reasoning.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
ln is your clue
anonymous
  • anonymous
I know it should be shifted by 3 to the right and the answer in the back of the book shows that as a vertical asymptote (x = 3), and I know multiplying by 2 will make the function larger. I just don't understand why x = 3 becomes the vertical asymptote and not the x intercept.
anonymous
  • anonymous
Because ln is always greater than 0

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amistre64
  • amistre64
ln(x) never equals 0 or less than 0
amistre64
  • amistre64
ln(x-3) is undefined at 3 and below
anonymous
  • anonymous
because you can't take ln(0) ?
amistre64
  • amistre64
you can try, but it like going to newyork to vist the grand canyon; when you get there, it aint gonna happen lol
anonymous
  • anonymous
So how could we write limit notation for the function?
amistre64
  • amistre64
lim[x->3] ln(x-3) = -inf if anything
amistre64
  • amistre64
that might have to be adjusted to say 'from the right'
anonymous
  • anonymous
This was actually a question from a graphing exercise. Trying to understand all of this so I can graph these correctly.
anonymous
  • anonymous
Thanks for the help!
amistre64
  • amistre64
yw :)
anonymous
  • anonymous
Amistre, you did so well on this and that triangle problem earlier, please take a look at this one, one guy is trying to find the answer, and I have tried everything http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4dd992160ada8b0bef2a41c7

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