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anonymous

  • 5 years ago

Find all asymptotes and intercepts: y = 2ln(x-3) How do I find the asymptotes and intercepts? I want to understand the reasoning.

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  1. anonymous
    • 5 years ago
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    ln is your clue

  2. anonymous
    • 5 years ago
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    I know it should be shifted by 3 to the right and the answer in the back of the book shows that as a vertical asymptote (x = 3), and I know multiplying by 2 will make the function larger. I just don't understand why x = 3 becomes the vertical asymptote and not the x intercept.

  3. anonymous
    • 5 years ago
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    Because ln is always greater than 0

  4. amistre64
    • 5 years ago
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    ln(x) never equals 0 or less than 0

  5. amistre64
    • 5 years ago
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    ln(x-3) is undefined at 3 and below

  6. anonymous
    • 5 years ago
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    because you can't take ln(0) ?

  7. amistre64
    • 5 years ago
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    you can try, but it like going to newyork to vist the grand canyon; when you get there, it aint gonna happen lol

  8. anonymous
    • 5 years ago
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    So how could we write limit notation for the function?

  9. amistre64
    • 5 years ago
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    lim[x->3] ln(x-3) = -inf if anything

  10. amistre64
    • 5 years ago
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    that might have to be adjusted to say 'from the right'

  11. anonymous
    • 5 years ago
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    This was actually a question from a graphing exercise. Trying to understand all of this so I can graph these correctly.

  12. anonymous
    • 5 years ago
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    Thanks for the help!

  13. amistre64
    • 5 years ago
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    yw :)

  14. anonymous
    • 5 years ago
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    Amistre, you did so well on this and that triangle problem earlier, please take a look at this one, one guy is trying to find the answer, and I have tried everything http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4dd992160ada8b0bef2a41c7

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