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anonymous

  • 5 years ago

I have a question we are doing quadratic equation and I have an example which I do not think it can be an quadratic equation. x^5+3x-7=0

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  1. anonymous
    • 5 years ago
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    Because I believe if you factor the equation it becomes x^5-4

  2. anonymous
    • 5 years ago
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    qudratic form : x^2 + x + C x^5 is def not quadratic

  3. anonymous
    • 5 years ago
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    so in other words you can't solve this equation?

  4. anonymous
    • 5 years ago
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    This x^5-3x+7=0 is in standard form?

  5. anonymous
    • 5 years ago
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    that is not in standard form for quadratic,

  6. toxicsugar22
    • 5 years ago
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    hey can u help me

  7. anonymous
    • 5 years ago
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    suzi20 I have a question for you but if you would take 5^2+3x+7=0 this is a quadratic equation correct?

  8. anonymous
    • 5 years ago
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    5^2+3x+7=0 yea this is quadratic

  9. anonymous
    • 5 years ago
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    the answer would be x=-3+i \[\sqrt{131}/10\]

  10. anonymous
    • 5 years ago
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    and -3-i sqrt 131/10

  11. anonymous
    • 5 years ago
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    suzi20 is that correct what I just posted for the answer

  12. anonymous
    • 5 years ago
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    sorry, i miss read, 5^2+3x+7=0 is not quadratic because 5^2 = 25 and this is constanta

  13. anonymous
    • 5 years ago
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    3x + 32 = 0 x = -32/3

  14. anonymous
    • 5 years ago
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    how would you create a quadratic equation that was not constata?

  15. anonymous
    • 5 years ago
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    5x^+3x-7=0 would this be a quadratic equation since the last sign was changed to minus instead of addition

  16. anonymous
    • 5 years ago
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    suzi20 or would it not make a difference would it still be constata?

  17. anonymous
    • 5 years ago
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    5x^2 + 3x - 7 is quadratic since u have variables x^2 and x 5^2 + 3x - 7 is linear because u just have 1 variable which is x

  18. anonymous
    • 5 years ago
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    then the answer would be x=-3+sqrt149/10, -3-sqrt149/10

  19. anonymous
    • 5 years ago
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    5x^2 + 3x - 7 a = 5 b= 3 c=-7 D = b^2 - 4ac = 9 + 140 = 149 x = -b +/- sqrt (D) over 2a = -3 +/- sqrt (149) over 10 x[1] = -3 + sqrt(149) over 10 x[2] = -3 - sqrt(149) over 10

  20. anonymous
    • 5 years ago
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    Thank you suzi20 you was a big help!

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