A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

solve for x: 16^x+4 = 3^2x-10...? help

  • This Question is Closed
  1. watchmath
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I suspect on the right should be 32^x

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh, yes

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its 16^x+4 = 32^2x-10

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ughh cmon

  5. watchmath
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    this is tough. Are you sure that this needs to be solved algebraically?

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, it says solve for x on my paper

  7. watchmath
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well, but you can solve by graphing too...

  8. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[16^{x} + 4 = 32^{2x}-10\] or \[16^{x+4} = 32^{2x-10}\] or \[x ^{16} + 4 = 2x ^{32} -10\] which one is it?

  9. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hi watchmath, im in a disagreement with amistre about integration region of revolution

  10. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    tje secound one audia

  11. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the secound

  12. watchmath
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh the second! then it is solvable I guess ....

  13. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i want to revolve the region bounded by y = x+2 and y = x^2 about the y axis , this is not possible. since it annulls itself . amistre thinks it is possible

  14. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you cant revolve a curve that is in Q2 or Q3 about the y axis, since then volume is not meaningful . the shell method for instance will output a negative ( i believe)

  15. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    forget it.. ill just try and figure this out.

  16. watchmath
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If it is the second equation, then we have \(4^{2x+8}=4^{5x-25}\) Hence \(2x+8=5x-25\) \(3x=33\) \(x=11\)

  17. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how did you get that?

  18. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how did you turn it into 4^2x+8 = 4^5x-25?

  19. watchmath
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \(16^{x+4}=(4^2)^{x+4}=2^{2(x+4)}=4^{2x+8}\) Try to figure out the second one :D.

  20. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.