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anonymous
 5 years ago
solve for x: 16^x+4 = 3^2x10...? help
anonymous
 5 years ago
solve for x: 16^x+4 = 3^2x10...? help

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watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0I suspect on the right should be 32^x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its 16^x+4 = 32^2x10

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0this is tough. Are you sure that this needs to be solved algebraically?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, it says solve for x on my paper

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0well, but you can solve by graphing too...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[16^{x} + 4 = 32^{2x}10\] or \[16^{x+4} = 32^{2x10}\] or \[x ^{16} + 4 = 2x ^{32} 10\] which one is it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hi watchmath, im in a disagreement with amistre about integration region of revolution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tje secound one audia

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0oh the second! then it is solvable I guess ....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i want to revolve the region bounded by y = x+2 and y = x^2 about the y axis , this is not possible. since it annulls itself . amistre thinks it is possible

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you cant revolve a curve that is in Q2 or Q3 about the y axis, since then volume is not meaningful . the shell method for instance will output a negative ( i believe)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0forget it.. ill just try and figure this out.

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0If it is the second equation, then we have \(4^{2x+8}=4^{5x25}\) Hence \(2x+8=5x25\) \(3x=33\) \(x=11\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you turn it into 4^2x+8 = 4^5x25?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0\(16^{x+4}=(4^2)^{x+4}=2^{2(x+4)}=4^{2x+8}\) Try to figure out the second one :D.
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