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anonymous
 5 years ago
what is the square root of x^4 + 7?
anonymous
 5 years ago
what is the square root of x^4 + 7?

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so 4+7 is 11 and the square root of 11 is? what are 2 of the same #s that divide into 11?like the square root of 36 is 6 bcuz 6 times 6 is 36.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x ^{4}+7}\] or\[\sqrt{x ^{4+7}}\]??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0na I need a specific answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is apparently factorable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is no good way to simplify that problem. It is simply \[\sqrt(x^4+7)\] Owlfred, your reply was useless. Helpneededlady, 11 is prime, and that was not this persons question anyway. Jman, is there more to the problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats it I have to simplify it further

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find f(√x + 2) if f(x) = x4 + 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0only it is x to the fourth

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well then you already gave us the solution to your problem, and it cannot be simplified further.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no it has to be simplified

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I did notice some calculation errors, that could be your problem. The answer ends up being \[(\sqrt(x+2))^4+5\]. At this point you can simplify and get a different answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(√x + 2) if f(x) = x4 + 5 (√x + 2)^4 + 5 = (x+2)^2 +5 = x^2 + 2x +9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont think we r allowed to do that suzi

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why? f(√x + 2) means x = √x + 2 then plug into equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0suzi, (sqrtx + 2)^4 is not (x + 2)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Guyc is correct, my bad I didn't notice the calculation errors, but her general procedure was correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0√x + 2 = (x+2)^1/2 (√x + 2)^4 = ((x+2)^1/2)^4 (x+2)^ 1/2 * 4 (x+2)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok up to u, that was my answer and thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The difficulty we're having is calculating (sqrt x + 2) ^4. Multiplying by hand by brute force I get: x^2 + 8x^(3/2) + 24x + 32x^(1/2) + 16 which is horrible
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