anonymous
  • anonymous
what is the square root of x^4 + 7?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Owlfred
  • Owlfred
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anonymous
  • anonymous
okay so 4+7 is 11 and the square root of 11 is? what are 2 of the same #s that divide into 11?like the square root of 36 is 6 bcuz 6 times 6 is 36.
anonymous
  • anonymous
(x^4 + 7)^1/2

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radar
  • radar
\[\sqrt{x ^{4}+7}\] or\[\sqrt{x ^{4+7}}\]??
anonymous
  • anonymous
na I need a specific answer
anonymous
  • anonymous
it is apparently factorable
anonymous
  • anonymous
There is no good way to simplify that problem. It is simply \[\sqrt(x^4+7)\] Owlfred, your reply was useless. Helpneededlady, 11 is prime, and that was not this persons question anyway. Jman, is there more to the problem?
anonymous
  • anonymous
no
anonymous
  • anonymous
thats it I have to simplify it further
anonymous
  • anonymous
Find f(√x + 2) if f(x) = x4 + 5
anonymous
  • anonymous
that is the problem
anonymous
  • anonymous
only it is x to the fourth
anonymous
  • anonymous
Well then you already gave us the solution to your problem, and it cannot be simplified further.
anonymous
  • anonymous
no it has to be simplified
anonymous
  • anonymous
I did notice some calculation errors, that could be your problem. The answer ends up being \[(\sqrt(x+2))^4+5\]. At this point you can simplify and get a different answer.
anonymous
  • anonymous
f(√x + 2) if f(x) = x4 + 5 (√x + 2)^4 + 5 = (x+2)^2 +5 = x^2 + 2x +9
anonymous
  • anonymous
i dont think we r allowed to do that suzi
anonymous
  • anonymous
why? f(√x + 2) means x = √x + 2 then plug into equation
anonymous
  • anonymous
suzi, (sqrtx + 2)^4 is not (x + 2)^2
anonymous
  • anonymous
Guyc is correct, my bad I didn't notice the calculation errors, but her general procedure was correct.
anonymous
  • anonymous
√x + 2 = (x+2)^1/2 (√x + 2)^4 = ((x+2)^1/2)^4 (x+2)^ 1/2 * 4 (x+2)^2
anonymous
  • anonymous
it was wrong
anonymous
  • anonymous
ok up to u, that was my answer and thank you.
anonymous
  • anonymous
The difficulty we're having is calculating (sqrt x + 2) ^4. Multiplying by hand by brute force I get: x^2 + 8x^(3/2) + 24x + 32x^(1/2) + 16 which is horrible

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