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(x^4 + 7)^1/2

\[\sqrt{x ^{4}+7}\] or\[\sqrt{x ^{4+7}}\]??

na I need a specific answer

it is apparently factorable

no

thats it I have to simplify it further

Find f(√x + 2) if f(x) = x4 + 5

that is the problem

only it is x to the fourth

Well then you already gave us the solution to your problem, and it cannot be simplified further.

no it has to be simplified

f(√x + 2) if f(x) = x4 + 5
(√x + 2)^4 + 5
= (x+2)^2 +5
= x^2 + 2x +9

i dont think we r allowed to do that suzi

why?
f(√x + 2) means x = √x + 2
then plug into equation

suzi, (sqrtx + 2)^4 is not (x + 2)^2

√x + 2 = (x+2)^1/2
(√x + 2)^4 = ((x+2)^1/2)^4
(x+2)^ 1/2 * 4
(x+2)^2

it was wrong

ok up to u, that was my answer and thank you.