what is the square root of x^4 + 7?

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what is the square root of x^4 + 7?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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okay so 4+7 is 11 and the square root of 11 is? what are 2 of the same #s that divide into 11?like the square root of 36 is 6 bcuz 6 times 6 is 36.
(x^4 + 7)^1/2

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Other answers:

\[\sqrt{x ^{4}+7}\] or\[\sqrt{x ^{4+7}}\]??
na I need a specific answer
it is apparently factorable
There is no good way to simplify that problem. It is simply \[\sqrt(x^4+7)\] Owlfred, your reply was useless. Helpneededlady, 11 is prime, and that was not this persons question anyway. Jman, is there more to the problem?
no
thats it I have to simplify it further
Find f(√x + 2) if f(x) = x4 + 5
that is the problem
only it is x to the fourth
Well then you already gave us the solution to your problem, and it cannot be simplified further.
no it has to be simplified
I did notice some calculation errors, that could be your problem. The answer ends up being \[(\sqrt(x+2))^4+5\]. At this point you can simplify and get a different answer.
f(√x + 2) if f(x) = x4 + 5 (√x + 2)^4 + 5 = (x+2)^2 +5 = x^2 + 2x +9
i dont think we r allowed to do that suzi
why? f(√x + 2) means x = √x + 2 then plug into equation
suzi, (sqrtx + 2)^4 is not (x + 2)^2
Guyc is correct, my bad I didn't notice the calculation errors, but her general procedure was correct.
√x + 2 = (x+2)^1/2 (√x + 2)^4 = ((x+2)^1/2)^4 (x+2)^ 1/2 * 4 (x+2)^2
it was wrong
ok up to u, that was my answer and thank you.
The difficulty we're having is calculating (sqrt x + 2) ^4. Multiplying by hand by brute force I get: x^2 + 8x^(3/2) + 24x + 32x^(1/2) + 16 which is horrible

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