anonymous
  • anonymous
1/x squared - 25 minus x+5/x squared - 4x-5?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
shadowfiend
  • shadowfiend
Eep. Could you use the equation editor here to write that out? It's not exactly clear what fractions go where and such.
anonymous
  • anonymous
\[1/x ^{2}-25 - x +5/x ^{2}-4x -5\]
shadowfiend
  • shadowfiend
Heh. Silly me. No fraction notation in the equation editor yet. This: \[\frac{1}{x^2} - 25−x+\frac{5}{x^2}−4x−5\] ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
well i dont know if it makes a difference but -25 is on the bottom of the left fraction next to x squared, then x + 5 all over x squared -4x - 5...... if that makes any sense
shadowfiend
  • shadowfiend
Absolutely! Here we go: \[\frac{1}{x^2 - 25} - \frac{x + 5}{x^2 - 4x - 5}\] Look right? What do you want to find out about this?
shadowfiend
  • shadowfiend
At a glance, the first thing that stands out is that \(x^2 - 25\) is \((x + 5)(x - 5)\), part of which is the same as the top of the right fraction. Also, if you factor the denominator of the right fraction, you get: \[x^2 - 4x - 5 = (x - 5)(x + 1)\] So now you have a common factor for the denominators as well. You should be able to do some interesting stuff once you write it out that way: \[\frac{1}{(x + 5)(x - 5)} - \frac{x + 5}{(x - 5)(x + 1)}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.