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anonymous

  • 5 years ago

1/x squared - 25 minus x+5/x squared - 4x-5?

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  1. shadowfiend
    • 5 years ago
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    Eep. Could you use the equation editor here to write that out? It's not exactly clear what fractions go where and such.

  2. anonymous
    • 5 years ago
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    \[1/x ^{2}-25 - x +5/x ^{2}-4x -5\]

  3. shadowfiend
    • 5 years ago
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    Heh. Silly me. No fraction notation in the equation editor yet. This: \[\frac{1}{x^2} - 25−x+\frac{5}{x^2}−4x−5\] ?

  4. anonymous
    • 5 years ago
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    well i dont know if it makes a difference but -25 is on the bottom of the left fraction next to x squared, then x + 5 all over x squared -4x - 5...... if that makes any sense

  5. shadowfiend
    • 5 years ago
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    Absolutely! Here we go: \[\frac{1}{x^2 - 25} - \frac{x + 5}{x^2 - 4x - 5}\] Look right? What do you want to find out about this?

  6. shadowfiend
    • 5 years ago
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    At a glance, the first thing that stands out is that \(x^2 - 25\) is \((x + 5)(x - 5)\), part of which is the same as the top of the right fraction. Also, if you factor the denominator of the right fraction, you get: \[x^2 - 4x - 5 = (x - 5)(x + 1)\] So now you have a common factor for the denominators as well. You should be able to do some interesting stuff once you write it out that way: \[\frac{1}{(x + 5)(x - 5)} - \frac{x + 5}{(x - 5)(x + 1)}\]

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