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anonymous
 5 years ago
1/x squared  25 minus x+5/x squared  4x5?
anonymous
 5 years ago
1/x squared  25 minus x+5/x squared  4x5?

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shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Eep. Could you use the equation editor here to write that out? It's not exactly clear what fractions go where and such.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/x ^{2}25  x +5/x ^{2}4x 5\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Heh. Silly me. No fraction notation in the equation editor yet. This: \[\frac{1}{x^2}  25−x+\frac{5}{x^2}−4x−5\] ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i dont know if it makes a difference but 25 is on the bottom of the left fraction next to x squared, then x + 5 all over x squared 4x  5...... if that makes any sense

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Absolutely! Here we go: \[\frac{1}{x^2  25}  \frac{x + 5}{x^2  4x  5}\] Look right? What do you want to find out about this?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0At a glance, the first thing that stands out is that \(x^2  25\) is \((x + 5)(x  5)\), part of which is the same as the top of the right fraction. Also, if you factor the denominator of the right fraction, you get: \[x^2  4x  5 = (x  5)(x + 1)\] So now you have a common factor for the denominators as well. You should be able to do some interesting stuff once you write it out that way: \[\frac{1}{(x + 5)(x  5)}  \frac{x + 5}{(x  5)(x + 1)}\]
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