## anonymous 5 years ago Find the product: 2y^2(y^4-y^3-4y^2+4y+5)

Just multiply it out. So: $2y^2(y^4 - y^3 - 4y^2 + 4y + 5)$ You have to distribute the $$2y^2$$ throughout the parenthesized part: $2y^2 \cdot y^4 - 2y^2 \cdot y^3 - 2y^2 \cdot 4y^2 + 2y^2 \cdot 4y + 2y^2 \cdot 5$ Can you go ahead and do those multiplications?

2. anonymous

do i add or multiply the exponents?

When you multiply two different powers of the same number (or variable), you add the exponents. You would multiply them if you double raised. So: $3x^2 \cdot x^5 = 3x^{2 + 5} = 3x^7$ $(x^2)^5 = x^{2\cdot 5} = x^{10}$

4. anonymous

2y^2(y^4-y^3-4y^2+4y+5) 2y^6-2y^5-8y^6+8y^310y^2??