A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
square root of 5 x 4= 4 x _. illustrate the commutative property.
anonymous
 5 years ago
square root of 5 x 4= 4 x _. illustrate the commutative property.

This Question is Closed

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{5x*4} ? or \sqrt{5*4}?\]

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.1if it is the 1st:= 2sqr(5x) id it is the 2nd:=2sqr5... hope ur looking 4 this :)

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0hi angela can u help me

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.04x^26y^2+32x24y+16=0 give the exact coordinated of an four points

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.04x^26y^2+32x24y+16=0 give the exact coordinates of any four points on the hyperbole

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0ok then nobody will help me

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.1let me see some formulas 1st pls...i don't remember them well

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0ok well then i am going to go

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0so i will see u later

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.1(4X^2 +32X +64)64=(X+4)^2  64....do the same for y....and u'll get the right eq. of hiperbole.... c^2a^2=b^2,hiperbola intercepts (Ox) at (a;0) and (a;0) I'm really late 4 school and i haevn't had breakfast yet...I'll see it later :) I'm sorry
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.