anonymous
  • anonymous
(y^4+3y-1)/(y^2-3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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dumbcow
  • dumbcow
im guessing polynomial division
anonymous
  • anonymous
dumbcow is right, (y^4+3y-1)/(y^2-3) = y^2 + 3 + (3y + 8/y^2 - 3)
dumbcow
  • dumbcow
for most part its same steps as regular long division do you need help with the steps

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dumbcow
  • dumbcow
nothingmaster gave you the correct answer if thats all you need
anonymous
  • anonymous
im not sure how that answer is correct
dumbcow
  • dumbcow
(y^2-3)(y^2 +3 +(3y+8/y^2-3)) =y^4 +3y^2 -3y^2 -9 +(3y+8) =y^4 +3y -1 which is the original numerator so quotient is correct

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