anonymous
  • anonymous
r(squared)-4r+c find the value of c that completes the square. how do you do this? :/
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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angela210793
  • angela210793
hmmm....w8...
angela210793
  • angela210793
c=2 (r-2)^2=r^2-2*r*2+2^2)=r^2-4r+4 :) i guess :):):)
dumbcow
  • dumbcow
(r+a)^2 = r^2 + 2ar +a^2 for this problem 2a = -4 a^2 = c 2a = -4 a = -2 c = (-2)^2 = 4

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angela210793
  • angela210793
oops yea c=2^2=4 :) sorry :)
anonymous
  • anonymous
wait what does ^ stand for???
angela210793
  • angela210793
@dumbcow u explain that please idk the word in english(english it's not my birth language) tht's y :)
angela210793
  • angela210793
4 example 2^2=4 3^2=9 like squared or not...depends
dumbcow
  • dumbcow
its for exponents
angela210793
  • angela210793
exactly!!! :)i just learnt a new word :) ^_^
anonymous
  • anonymous
ohh got it got it, thanks guyys [: are you both students? high school ?
angela210793
  • angela210793
yea 12th grade :S :S
dumbcow
  • dumbcow
im a student but way past high school, haha
anonymous
  • anonymous
Haha I see. I am an upcoming junior .
angela210793
  • angela210793
:)
dumbcow
  • dumbcow
nice, yeah this is a pretty good place to get help with hw and math questions lot of good math people here
anonymous
  • anonymous
Yeah I can see that, I really like this website .

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