using five function values estimate

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

using five function values estimate

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\int\limits_{-3}^{3}\sqrt{9-x ^{2}}\] using: (i)the trapezoidal rule (ii) simpsons rule
the values are: x -3 -1.5 0 1.5 3 y Sqrt(18) Sqrt(45)/2 3 Sqrt(27)/2 0
my values maybe wrong so you might have to double check

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Integrations....the thing i hate in most....:S
my attempt: \[\int\limits_{-3}^{3}\sqrt{9-x ^{2}}\approx \int\limits_{-3}^{-1.5}\sqrt{9-x ^{2}}+\int\limits_{-1.5}^{0}\sqrt{9-x ^{2}}+\int\limits_{0}^{1.5}\sqrt{9-x ^{2}}+\int\limits_{1.5}^{3}\sqrt{9-x ^{2}}\]
why did u change 3 to -1.5?
really i think its quite enjoyable :)
its my attempt using the trapezoidal rule
it was the lowest grade i had ever taken in math....tht's y i don't like it :S:S...let me try my way plssss
i have the answer using the easy way now i need to learn this method for an exam lol unfortunantely its not optional
ok...I have forgotten the formulas anyway...so i can't solve it even though i tried....and i really have never seen this way of solution...maybe u in USA r smarter :P:P
im not from the US lol
ok..in that country from wherever u are...u seem to b smarter :P:P
following from the top i get \[\int\limits_{-3}^{3}\sqrt{9-x ^{2}}\approx 3/4(\sqrt{18}+\sqrt{45}/2)+3/4(3+\sqrt{45}/2)+3/4(3+\sqrt{27}/2)+3/4(\sqrt{27}/2+0)\]
thats my working for the trapezoidal rule
looks good where did the 3/4 come from? shouldnt it be 1/b-a
the answer in the back: \[\approx12.294\] whilst i get \[\approx16.610\]
nevermind
the rule in my textbook is \[\int\limits_{a}^{b}f(x)dx \approx( (b-a)/2) (f(a)+f(b))\]
so using this the first part is (-1.5-(-3))/2 =3/4
yep thats it
but my answer is way off im dont know what im doing wrong
oh your y values are off x=-3 y=0
9-(-3)^2 =9-9
omg i knew i should have put brackets around them lol
i will try it again lol
i have to thankyou again dumbcow you my friend are a genius :)
O.o I really have never seen this before.....O.o
well im in australia and we do a wide range of mathematics
btw the two rules above are just approximations of the integrals theyre always abit off lol
I HATE integrations..i always will..i hope tht I won't have to solve any of them in math exam :S
haha no love for the integrals your welcome and
lol i actually reckon its a fun part of maths when you get it right. i hate vector geometry
i hate conical lines as well (is this how u call them?) O.o
ill assume you mean conics lol
idk... :$ maybe...let me google a bit plssss
kk
hyperbole, ellipse, parabola....these are wht i am talking abt....they r called conics?
yeah they are theyre not too bad what country are you from
No they are...too many formulas...then tangents.....i hate them....actually thr's nothing i like in math :P..I'm from Albania/Europe :)
I learnt another word...thanks :)
cool it sounds interesting
:)

Not the answer you are looking for?

Search for more explanations.

Ask your own question