Write the equation of a line in slope-intercept form that is perpendicular to y=-5/6x+2 and passes through (12, -4).

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Write the equation of a line in slope-intercept form that is perpendicular to y=-5/6x+2 and passes through (12, -4).

Mathematics
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ah! i hate perpendicular!!! and does the perpindicular lines has to be = to -1 if yes i can help
^^ aroub idk, i think so!
almost aroub - if the slope of a line is m then the slope of perpendicular = -1/m

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ya it has to be = to -1
so its y=-1 ??
idk i really forgot the perpendicular
no the slope of the perpendicular linr wiil be -1/(-5/6) which simplifies to 6/5
ya i think your right because if u simplified it it will be = -1
so its y=-1x+-5/6 ?
no the 5/6 is the coefficient of x i.e. (6/5)x the equation u want is y = (6/5)x + 2
your AWSOME (: (: thanks alot (:
the general form of the slope-intercept equation is y = mx +c where m = slope of the line and c is the intercept on the y-axis
no probs bailey
thanks (: can you help with one last problem like this?
yes ok
Write the equation of a line in slope-intercept form that is perpendicular to 3x+2y=6 and passes through the point (3, 0).
thanks (:
first manipulate the equation to get it in y=mx+c form divide by 2 (because we have 2x): 3x/2 + y = 3 y = -(3/2)x + 3 -so we can see that the slope = -(3/2) and the intercept on the y axis 3. slope of perpndclr. = -1/-(3/2) = 2/3 so our equation is y = (2/3)x + 3
sorry on line 2 I should have put 2y not 2x
to get rid of the fraction we can multiply each term of the equation b 3 3y = 2x + 9 this is equivalent to the fractional equation
thankss (:
the questions are a bit strange though - you do not need the coordinates of the point to work out the problem
okay (:
if you have a similar problem which gives you the equation and a point on the line you use another form of the formula i e y - y1 = m(x - x1) where m = slope of the line and (x1,y1) are the coordinates of the given point
yes this is the easiest way to do it i agree:)

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