anonymous
  • anonymous
Write the equation of a line in slope-intercept form that is perpendicular to y=-5/6x+2 and passes through (12, -4).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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aroub
  • aroub
ah! i hate perpendicular!!! and does the perpindicular lines has to be = to -1 if yes i can help
anonymous
  • anonymous
^^ aroub idk, i think so!
anonymous
  • anonymous
almost aroub - if the slope of a line is m then the slope of perpendicular = -1/m

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aroub
  • aroub
ya it has to be = to -1
anonymous
  • anonymous
so its y=-1 ??
aroub
  • aroub
idk i really forgot the perpendicular
anonymous
  • anonymous
no the slope of the perpendicular linr wiil be -1/(-5/6) which simplifies to 6/5
aroub
  • aroub
ya i think your right because if u simplified it it will be = -1
anonymous
  • anonymous
so its y=-1x+-5/6 ?
anonymous
  • anonymous
no the 5/6 is the coefficient of x i.e. (6/5)x the equation u want is y = (6/5)x + 2
anonymous
  • anonymous
your AWSOME (: (: thanks alot (:
anonymous
  • anonymous
the general form of the slope-intercept equation is y = mx +c where m = slope of the line and c is the intercept on the y-axis
anonymous
  • anonymous
no probs bailey
anonymous
  • anonymous
thanks (: can you help with one last problem like this?
anonymous
  • anonymous
yes ok
anonymous
  • anonymous
Write the equation of a line in slope-intercept form that is perpendicular to 3x+2y=6 and passes through the point (3, 0).
anonymous
  • anonymous
thanks (:
anonymous
  • anonymous
first manipulate the equation to get it in y=mx+c form divide by 2 (because we have 2x): 3x/2 + y = 3 y = -(3/2)x + 3 -so we can see that the slope = -(3/2) and the intercept on the y axis 3. slope of perpndclr. = -1/-(3/2) = 2/3 so our equation is y = (2/3)x + 3
anonymous
  • anonymous
sorry on line 2 I should have put 2y not 2x
anonymous
  • anonymous
to get rid of the fraction we can multiply each term of the equation b 3 3y = 2x + 9 this is equivalent to the fractional equation
anonymous
  • anonymous
thankss (:
anonymous
  • anonymous
the questions are a bit strange though - you do not need the coordinates of the point to work out the problem
anonymous
  • anonymous
okay (:
anonymous
  • anonymous
if you have a similar problem which gives you the equation and a point on the line you use another form of the formula i e y - y1 = m(x - x1) where m = slope of the line and (x1,y1) are the coordinates of the given point
aroub
  • aroub
yes this is the easiest way to do it i agree:)

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