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anonymous
 5 years ago
I am not a student or a minor, I just need help with an algebraic percentage problem, can you help?
anonymous
 5 years ago
I am not a student or a minor, I just need help with an algebraic percentage problem, can you help?

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am a certified weld inspector, and this is a real world problem.... I have a sum of 385852 pounds of welding wire used last year at different rates of consumption. I need an average consumption of this gross. 148,864 were used at 13.53 pounds per hour, and 236,988 were used at 9.53 pounds per hour

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what would the overall average rate of consumption be for this lot of welding wire?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0given 2 data points; the best solution would be a linear function right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I beleive... its been a long time since I have used algebra (sorry)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if we knew the total hours for last year we might be able to fit it to a quadratic function; or use statistical measures to get a best fit line...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know that the different values have to be weighted per their value against the whole

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0theres not enough data to get any relevant statistical measurements from tho, weigthed or not... i believe

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we could use the point 0 pounds for 0 hours right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we dont need to figure rate, just an overall average of the rate

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the rate of change depends on the type of function that best fits the data... if that function is linear, then we have a line; if its curved then we gotta bend the line to fit...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sum = 385852 pounds used at the following rates (to make 100%) 148,864 @ 13.53 pounds per hour, and 236,988 @ 9.53 pounds per hour

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need an average pounds per hour for the whole 385,852

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0When I fit this data to a quadratic I pretty much get this result for x = hours 3466.265785332662 x^2 + 57901.08900977116 x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if i flip my data for x = pounds I can get one to estimate the whole of 385k

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05.750456292871241e10x^2 + 0.00017649192015923025x at an hour output of: 17.514048386364664; which leads me to believe that what im thinking of is quite possibly wrong :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but then the rate does increase as the hours drop so it might be an accurate portrayal of the data point

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=5.750456292871241e10x^2+%2B+0.00017649192015923025x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its either that or add the data points to each other and /2 to get the midpoint

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0148,864 @ 13.53 236,988 @ 9.53  (385852 @ 23.06)/2 = (192926 @ 11.53)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0148864 pounds  = 11002.51 hours 13.53 pounds / hour 236988 pounds  = 24867.57 hours 9.53 pounds / hour total hours = 11002.51 + 24867.57 = 35870.08 385852 pounds  = 10.756 pounds / hour 35870.08 hours

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0planechkr, I'll let you click `good answer' for the answer that helped you the most :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0fiddles looks to be a better interpretation of the information given :)
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