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anonymous
 5 years ago
Please help me integrating this:
anonymous
 5 years ago
Please help me integrating this:

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?} cosx dx / sinx (2+sinx)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's an indefinite integral

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Use substitution \(u=\sin x\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey watch, do you know how to view old questions, in your settings ?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1old questions that you asked or old questions that you answered?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for instance that induction problem we were working on, is lost

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1I can see it, by the link is related to my profile. Try to click the link here : http://openstudy.com/users/watchmath#/users/watchmath/updates/4dd9bc1c0ada8b0b731c42c7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so did that question make sense earlier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the product of e^(r/n) *1/n = y , they took the log of both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it isnt quite exactly the integral since i thought you need a right hand or left hand sum

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ln y = 1/n [ e^0/n + e^(1/n) + ... e^n/n)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the right hand side is not quite a riemann sum,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lim n> oo 1/n [ e^0/n + e^(1/n) + ... e^n/n)

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Let's continue on the old thread: http://openstudy.com/users/watchmath#/users/watchmath/updates/4dda53c30ada8b0b11c243c7
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