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anonymous

  • 5 years ago

(2x^3+3x^2-19x-1) / (x-4)

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  1. anonymous
    • 5 years ago
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    do you know how to use synthetic division?

  2. roadjester
    • 5 years ago
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    i was gonna ask that! *pouts*

  3. anonymous
    • 5 years ago
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    2 3 -19 -1 4 8 44 100 ________________________________ 2 11 25 99

  4. anonymous
    • 5 years ago
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    yes but its scketchy

  5. anonymous
    • 5 years ago
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    list the coefficients, which is the top line 2 3 -19 -1

  6. anonymous
    • 5 years ago
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    then since you are dividing by \[x-4\] put a 4 on the side

  7. anonymous
    • 5 years ago
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    bring down the 2 to the bottom line. 2 3 -19 -1 4 _____________________________ 2

  8. anonymous
    • 5 years ago
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    \[2\times 4 =8\] 2 3 -19 -1 4 8 ___________________________ 2

  9. anonymous
    • 5 years ago
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    \[8+3=11\] 2 3 -19 -1 4 8 ___________________________ 2 11

  10. anonymous
    • 5 years ago
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    \[4\times 11 = 44\] 2 3 -19 -1 4 8 44 ___________________________ 2 11

  11. anonymous
    • 5 years ago
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    \[-19+44=25\] 2 3 -19 -1 4 8 44 ___________________________ 2 11 25

  12. anonymous
    • 5 years ago
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    \[4\times 25=100\] 2 3 -19 -1 4 8 44 100 ___________________________ 2 11 25

  13. anonymous
    • 5 years ago
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    \[-1+100=99\] 2 3 -19 -1 4 8 44 100 ___________________________ 2 11 25 99

  14. anonymous
    • 5 years ago
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    you have divided a polynomial of degree 3 by a polynomial of degree 1 so your answer is a polynomial of degree 2 thus \[2x^2+11x+25+\frac{99}{x-4}\]

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