anonymous
  • anonymous
can someone give me a formula for this please? A college student earned $8400 during summer vacation working as a waiter in a popular restaurant. Part was invested at 8% simple interest and the remainder at 9% simple interest. At the end of one year, the student had earned $707 interest. How much was invested at 9%
Mathematics
katieb
  • katieb
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Owlfred
  • Owlfred
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anonymous
  • anonymous
707=0.08(8400 +0.09(8400)
anonymous
  • anonymous
not possible

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amistre64
  • amistre64
the formula(s) would be: a + b = 8400; a = 8400-b 707 = a(.08) + b(.09) ; substitue the 'value' of a into this equation and solve for 'b'
anonymous
  • anonymous
oops yes it is sorry. call the amount invested at 9% x. then \.09x+.08(8400-x)=707\]
anonymous
  • anonymous
\[.09x+.08(8400-x)=707\] \[.01x+672=707\] \[.01x=35\] \[x=\frac{35}{.01}=3500\]

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