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depends on what I have to do with smth :)
O.o..let me attach the problem pls...
it is a rhomb ***
i could see this as looking for the radius; which would indicate the a triangle in Q1
its a 3-4-5 right triangle
we then find the max area of a square that fits in it...maybe; or the max part of the circle to fit it
w8..i think i got how to solve it....all we have to do is find the height at ODC triangle and that=r :)
And then S=pi*r^2
this was what u were talking abt 2? Thnx a loot :)
the equation of the line that we want is: (0,3) ; (4,0) ; the slope then being 3/4 or.... y = -(3/4)x + 3 right? that is the equation for the hyp ... that line of 5
we want a perp line to this that goes thru the origin (0,0) if anything
y = (4/3)x
the distance R is the distance from the origin to the point where these 2 lines meet right?
(4/3)x = (3/4)x +3 dunno yet still figuring this out the hard way lol
I think it should be -(3/4)x=(4/3)x+4 Amistre...
w8 is easy...S(odc)= B*H/2=3*4/2=6 S(odc) is also=OE*DC/2=6----> OE=12/DC=12/5
the slope of the hyp I drew is -3/4 with a y int at (0,3) right?
I didn't get ur way......:(:(:( why with coordinates? O.o :(
my way is sound to me; i understand graphs and lines better than drawings
Your solution is nice angela :)
Wht abt my way? is it wrong?
Oh thnx :) :)
4 up and 3 over is the same region as 3 up and 4 over, ...
i dont really know if your way is right or wrong yet ;)
Her solution based on computing the area of ODC in two ways. First: 1/2*3*4 Second* 1/2*CD*r = 1/2*5*r
(4/3)x = (-3/4)x + 3  4x = (-9/4)x +9  16x = -9x + 36 25x = 36 x = 36/25 did I get that right?
I didn't get ur way so i can't tell it if it is right or not.... Thank u very much anyway :):):):)
Amistre, the y-intercept is at (0,4)
4 36 -- * --- = y 3 25 4 12 -- * --- = y = 48/25 1 25 R = sqrt(x^2 + y^2) R = sqrt((36/25)^2+(48/25)^2)
watch; it can be; but im actually using the other side; even tho I inadvertantly flipped it; it doesnt matter if we have 4 over and 3; or 3 over and 4 up; its the same triangle just flipped on itself with the same amount of circle it it ...
its the point of tangency that is important; in my figuring
let me read it from the start once again...
Yes, your computation gives the same r :)
thank u both :)
R = 12/5 yay!! lol
so that verifies your answer angela :) I know my way is solid, which is why I went that route
Will u see another 1 with inflexion points? (Is this how u call it?)
inflection points are where the graph stays along a course in a general direction.. sure
^_^ ok w8 :)
f(x)=x^4+c*x^3+x^2 what should b X so it will have 2 inflect. points? and then 1?
'X' or 'c' ?
f'= 4x^3 +3cx^2 +2x f'' = 12x^2 +6cx +2 = 0 for inflection points
it says x...
x, as far as I can tell, is an input and has no real effect on the graph of this thing; the constants describe the path it takes
how are they defining inflection?
they who? O.o
they as in the people who designed the question, the authors of the material that you are using .... those guys
I see the answers; but the question should be what value should 'c' be...
C'mon...idk the words in english...............:S
ok u solve it 4 c...
f'' = 12x^2 +6cx +2 = 0 in order for this to have 2 real roots; we have to manipulate the discriminate of the quadratic formula....
36c^2 -4(2)(12) > 0 for 2 inflections 36c^2 -4(2)(12) = 0 for 1 inflection
36c^2 -96 = 0 36c^2 = 96 c^2 = 96/36 c = +- sqrt(96)/6 for one inflection
and greater than that for 2 inflections
whr did tht 36c^2 come from?O.o Florida? :P
it comes from taking the 1st and 2nd derivatives of the given equation
youd have to understand a little calculus to get the idea of it; but basically I used proven methods to find when the 2nd derivative = 0
y = x^4+c*x^3+x^2 y' = 4x^3 +3cx^2 +2x y'' = 12x^2 +6cx +2 ; when y'' = 0 we have a point of inflection
y'' is a quadratic that can have its roots figured out by the quadratic formula; the discriminant of the quad formula tells us how many roots we will have
b^2 -4ac (6c)^2 - 4(2)(12) 36c^2 -96 has to be greater than 0 for it to have 2 points for inflection 36c^2 -96 has to equal 0 for it to only have 1 point of inflection
so you solve the equations of the discriminate for c..
if we know what c is ro get the discriminate to = 0; then we should assume that larger values of c will make it greater then 0 for 2 roots
ahaaa.....i got it....Thnx ^_^
Will u help me in smth else?..... if u don't mind ofc...
i gotta finish my international business homework; its due today..
Oh..Ok..I'm sorry...didn't know tht.... Thnx a lot 4 helping me and good luck with ur hw :)
thnx :) and good luck with yours :)