angela210793
  • angela210793
@amistre64 will u help me in smth pls?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
depends on what I have to do with smth :)
angela210793
  • angela210793
O.o..let me attach the problem pls...
angela210793
  • angela210793
U have to find the area of the circle...
1 Attachment

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angela210793
  • angela210793
it is a rhomb ***
amistre64
  • amistre64
i could see this as looking for the radius; which would indicate the a triangle in Q1
amistre64
  • amistre64
its a 3-4-5 right triangle
amistre64
  • amistre64
we then find the max area of a square that fits in it...maybe; or the max part of the circle to fit it
angela210793
  • angela210793
w8..i think i got how to solve it....all we have to do is find the height at ODC triangle and that=r :)
angela210793
  • angela210793
And then S=pi*r^2
angela210793
  • angela210793
Right?
amistre64
  • amistre64
1 Attachment
angela210793
  • angela210793
this was what u were talking abt 2? Thnx a loot :)
amistre64
  • amistre64
the equation of the line that we want is: (0,3) ; (4,0) ; the slope then being 3/4 or.... y = -(3/4)x + 3 right? that is the equation for the hyp ... that line of 5
amistre64
  • amistre64
we want a perp line to this that goes thru the origin (0,0) if anything
amistre64
  • amistre64
y = (4/3)x
amistre64
  • amistre64
the distance R is the distance from the origin to the point where these 2 lines meet right?
angela210793
  • angela210793
ehe...
angela210793
  • angela210793
r=12/5?
amistre64
  • amistre64
(4/3)x = (3/4)x +3 dunno yet still figuring this out the hard way lol
watchmath
  • watchmath
I think it should be -(3/4)x=(4/3)x+4 Amistre...
angela210793
  • angela210793
w8 is easy...S(odc)= B*H/2=3*4/2=6 S(odc) is also=OE*DC/2=6----> OE=12/DC=12/5
amistre64
  • amistre64
the slope of the hyp I drew is -3/4 with a y int at (0,3) right?
angela210793
  • angela210793
I didn't get ur way......:(:(:( why with coordinates? O.o :(
amistre64
  • amistre64
my way is sound to me; i understand graphs and lines better than drawings
watchmath
  • watchmath
Your solution is nice angela :)
angela210793
  • angela210793
Wht abt my way? is it wrong?
angela210793
  • angela210793
Oh thnx :) :)
amistre64
  • amistre64
4 up and 3 over is the same region as 3 up and 4 over, ...
amistre64
  • amistre64
i dont really know if your way is right or wrong yet ;)
angela210793
  • angela210793
hmmmm.....
watchmath
  • watchmath
Her solution based on computing the area of ODC in two ways. First: 1/2*3*4 Second* 1/2*CD*r = 1/2*5*r
angela210793
  • angela210793
Ehe...
amistre64
  • amistre64
(4/3)x = (-3/4)x + 3 [3] 4x = (-9/4)x +9 [4] 16x = -9x + 36 25x = 36 x = 36/25 did I get that right?
angela210793
  • angela210793
I didn't get ur way so i can't tell it if it is right or not.... Thank u very much anyway :):):):)
watchmath
  • watchmath
Amistre, the y-intercept is at (0,4)
amistre64
  • amistre64
4 36 -- * --- = y 3 25 4 12 -- * --- = y = 48/25 1 25 R = sqrt(x^2 + y^2) R = sqrt((36/25)^2+(48/25)^2)
amistre64
  • amistre64
watch; it can be; but im actually using the other side; even tho I inadvertantly flipped it; it doesnt matter if we have 4 over and 3; or 3 over and 4 up; its the same triangle just flipped on itself with the same amount of circle it it ...
amistre64
  • amistre64
its the point of tangency that is important; in my figuring
angela210793
  • angela210793
let me read it from the start once again...
amistre64
  • amistre64
like this
1 Attachment
watchmath
  • watchmath
Yes, your computation gives the same r :)
angela210793
  • angela210793
thank u both :)
amistre64
  • amistre64
R = 12/5 yay!! lol
angela210793
  • angela210793
:D ^_^
amistre64
  • amistre64
so that verifies your answer angela :) I know my way is solid, which is why I went that route
angela210793
  • angela210793
Will u see another 1 with inflexion points? (Is this how u call it?)
amistre64
  • amistre64
inflection points are where the graph stays along a course in a general direction.. sure
angela210793
  • angela210793
^_^ ok w8 :)
angela210793
  • angela210793
f(x)=x^4+c*x^3+x^2 what should b X so it will have 2 inflect. points? and then 1?
amistre64
  • amistre64
'X' or 'c' ?
amistre64
  • amistre64
f'= 4x^3 +3cx^2 +2x f'' = 12x^2 +6cx +2 = 0 for inflection points
angela210793
  • angela210793
it says x...
amistre64
  • amistre64
x, as far as I can tell, is an input and has no real effect on the graph of this thing; the constants describe the path it takes
amistre64
  • amistre64
how are they defining inflection?
angela210793
  • angela210793
they who? O.o
amistre64
  • amistre64
they as in the people who designed the question, the authors of the material that you are using .... those guys
amistre64
  • amistre64
I see the answers; but the question should be what value should 'c' be...
angela210793
  • angela210793
C'mon...idk the words in english...............:S
angela210793
  • angela210793
ok u solve it 4 c...
amistre64
  • amistre64
f'' = 12x^2 +6cx +2 = 0 in order for this to have 2 real roots; we have to manipulate the discriminate of the quadratic formula....
amistre64
  • amistre64
36c^2 -4(2)(12) > 0 for 2 inflections 36c^2 -4(2)(12) = 0 for 1 inflection
amistre64
  • amistre64
36c^2 -96 = 0 36c^2 = 96 c^2 = 96/36 c = +- sqrt(96)/6 for one inflection
amistre64
  • amistre64
and greater than that for 2 inflections
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=sqrt%2896%2F36%29
angela210793
  • angela210793
whr did tht 36c^2 come from?O.o Florida? :P
amistre64
  • amistre64
it comes from taking the 1st and 2nd derivatives of the given equation
amistre64
  • amistre64
youd have to understand a little calculus to get the idea of it; but basically I used proven methods to find when the 2nd derivative = 0
amistre64
  • amistre64
y = x^4+c*x^3+x^2 y' = 4x^3 +3cx^2 +2x y'' = 12x^2 +6cx +2 ; when y'' = 0 we have a point of inflection
amistre64
  • amistre64
y'' is a quadratic that can have its roots figured out by the quadratic formula; the discriminant of the quad formula tells us how many roots we will have
amistre64
  • amistre64
b^2 -4ac (6c)^2 - 4(2)(12) 36c^2 -96 has to be greater than 0 for it to have 2 points for inflection 36c^2 -96 has to equal 0 for it to only have 1 point of inflection
amistre64
  • amistre64
so you solve the equations of the discriminate for c..
amistre64
  • amistre64
if we know what c is ro get the discriminate to = 0; then we should assume that larger values of c will make it greater then 0 for 2 roots
angela210793
  • angela210793
ahaaa.....i got it....Thnx ^_^
angela210793
  • angela210793
Will u help me in smth else?..... if u don't mind ofc...
amistre64
  • amistre64
i gotta finish my international business homework; its due today..
angela210793
  • angela210793
Oh..Ok..I'm sorry...didn't know tht.... Thnx a lot 4 helping me and good luck with ur hw :)
amistre64
  • amistre64
thnx :) and good luck with yours :)
angela210793
  • angela210793
^_^

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