## anonymous 5 years ago √7x^6y^3 8z

1. amistre64

I know what it means individually; but when you put them all together like that it just loses all rhyme and reason ...

2. anonymous

?

3. amistre64

my point exactly :) How do you expect anyone to make any sense of this question? You might as well asks: fiwjnduudhne&%9sdj2((

4. anonymous

R u making fun of me? I am new here so maybe I wrote it wrong but this is what it looks like in my book

5. amistre64

then you should burn your book.... its not making fun of you; its trying to figure out what is written and discern some sensible form or function to it...

6. amistre64

as is; its complete and utter gibberish

7. anonymous

$\sqrt{7x ^{6}y ^{3}}$ I don't know how to write the 8z underneath it..

8. amistre64

is it a divde by 8z? or is the 8z under the radical too?

9. amistre64

sqrt(7x^6 y^3) ------------- ?? or is the 8z included in the sqrt? 8z

10. anonymous

just like you wrote it that is what it looks like with the line underneath it..

11. amistre64

and I take it they want this to be simplified?

12. anonymous

yes

13. amistre64

$\frac{\sqrt{7x^6y^3}}{8z} \rightarrow \frac{x^2 y \sqrt{7y}}{8z}$

14. amistre64

or the other possibility is this....

15. amistre64

$\sqrt{\frac{7x^6y^3}{8z}} \rightarrow \frac{x^2y \sqrt{7y}}{2\sqrt{2z}}$

16. amistre64

it all depends on if the 8z is a part of the square root; or simply under it

17. anonymous

I think it's under it. The answer in the book is $x ^{3}y \sqrt{14yz}$ and under it is 4z

18. anonymous

just not sure on how they got it...

19. amistre64

its a part of it then..... and I typoed that first x; its x^3 ; then they do something called rationalizing the denom becasue they hate to see radicals in the bottom of a fraction

20. amistre64

it goes like this: $\frac{7^{1/2}x^{6/2}y^{3/2}}{8^{1/2}z^{1/2}} \rightarrow \frac{x^3 y \sqrt{7y}}{2 \sqrt{2z}} \rightarrow \frac{x^3y \sqrt{7y*2z}}{2} \rightarrow \frac{x^3y \sqrt{14yz}}{2}$

21. amistre64

the 4z under would be odd

22. anonymous

oh okay that makes sense :) Thank you

23. amistre64

lol.... I just got why 4z is on the bottom :) I forgot a step .....

24. amistre64

2 * sqrt(2z) * sqrt(2z) = 2*2z = 4z lol

25. anonymous

lol it's okay thanks for your help