√7x^6y^3
8z

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- anonymous

√7x^6y^3
8z

- chestercat

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- amistre64

I know what it means individually; but when you put them all together like that it just loses all rhyme and reason ...

- anonymous

?

- amistre64

my point exactly :) How do you expect anyone to make any sense of this question? You might as well asks:
fiwjnduudhne&%9sdj2((

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## More answers

- anonymous

R u making fun of me? I am new here so maybe I wrote it wrong but this is what it looks like in my book

- amistre64

then you should burn your book....
its not making fun of you; its trying to figure out what is written and discern some sensible form or function to it...

- amistre64

as is; its complete and utter gibberish

- anonymous

\[\sqrt{7x ^{6}y ^{3}}\] I don't know how to write the 8z underneath it..

- amistre64

is it a divde by 8z? or is the 8z under the radical too?

- amistre64

sqrt(7x^6 y^3)
------------- ?? or is the 8z included in the sqrt?
8z

- anonymous

just like you wrote it that is what it looks like with the line underneath it..

- amistre64

and I take it they want this to be simplified?

- anonymous

yes

- amistre64

\[\frac{\sqrt{7x^6y^3}}{8z} \rightarrow \frac{x^2 y \sqrt{7y}}{8z}\]

- amistre64

or the other possibility is this....

- amistre64

\[\sqrt{\frac{7x^6y^3}{8z}} \rightarrow \frac{x^2y \sqrt{7y}}{2\sqrt{2z}}\]

- amistre64

it all depends on if the 8z is a part of the square root; or simply under it

- anonymous

I think it's under it. The answer in the book is \[x ^{3}y \sqrt{14yz}\] and under it is 4z

- anonymous

just not sure on how they got it...

- amistre64

its a part of it then..... and I typoed that first x; its x^3 ; then they do something called rationalizing the denom becasue they hate to see radicals in the bottom of a fraction

- amistre64

it goes like this:
\[\frac{7^{1/2}x^{6/2}y^{3/2}}{8^{1/2}z^{1/2}} \rightarrow \frac{x^3 y \sqrt{7y}}{2 \sqrt{2z}} \rightarrow \frac{x^3y \sqrt{7y*2z}}{2} \rightarrow \frac{x^3y \sqrt{14yz}}{2}\]

- amistre64

the 4z under would be odd

- anonymous

oh okay that makes sense :) Thank you

- amistre64

lol.... I just got why 4z is on the bottom :) I forgot a step .....

- amistre64

2 * sqrt(2z) * sqrt(2z) = 2*2z = 4z lol

- anonymous

lol it's okay thanks for your help

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