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anonymous

  • 5 years ago

√7x^6y^3 8z

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  1. amistre64
    • 5 years ago
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    I know what it means individually; but when you put them all together like that it just loses all rhyme and reason ...

  2. anonymous
    • 5 years ago
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    ?

  3. amistre64
    • 5 years ago
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    my point exactly :) How do you expect anyone to make any sense of this question? You might as well asks: fiwjnduudhne&%9sdj2((

  4. anonymous
    • 5 years ago
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    R u making fun of me? I am new here so maybe I wrote it wrong but this is what it looks like in my book

  5. amistre64
    • 5 years ago
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    then you should burn your book.... its not making fun of you; its trying to figure out what is written and discern some sensible form or function to it...

  6. amistre64
    • 5 years ago
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    as is; its complete and utter gibberish

  7. anonymous
    • 5 years ago
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    \[\sqrt{7x ^{6}y ^{3}}\] I don't know how to write the 8z underneath it..

  8. amistre64
    • 5 years ago
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    is it a divde by 8z? or is the 8z under the radical too?

  9. amistre64
    • 5 years ago
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    sqrt(7x^6 y^3) ------------- ?? or is the 8z included in the sqrt? 8z

  10. anonymous
    • 5 years ago
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    just like you wrote it that is what it looks like with the line underneath it..

  11. amistre64
    • 5 years ago
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    and I take it they want this to be simplified?

  12. anonymous
    • 5 years ago
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    yes

  13. amistre64
    • 5 years ago
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    \[\frac{\sqrt{7x^6y^3}}{8z} \rightarrow \frac{x^2 y \sqrt{7y}}{8z}\]

  14. amistre64
    • 5 years ago
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    or the other possibility is this....

  15. amistre64
    • 5 years ago
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    \[\sqrt{\frac{7x^6y^3}{8z}} \rightarrow \frac{x^2y \sqrt{7y}}{2\sqrt{2z}}\]

  16. amistre64
    • 5 years ago
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    it all depends on if the 8z is a part of the square root; or simply under it

  17. anonymous
    • 5 years ago
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    I think it's under it. The answer in the book is \[x ^{3}y \sqrt{14yz}\] and under it is 4z

  18. anonymous
    • 5 years ago
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    just not sure on how they got it...

  19. amistre64
    • 5 years ago
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    its a part of it then..... and I typoed that first x; its x^3 ; then they do something called rationalizing the denom becasue they hate to see radicals in the bottom of a fraction

  20. amistre64
    • 5 years ago
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    it goes like this: \[\frac{7^{1/2}x^{6/2}y^{3/2}}{8^{1/2}z^{1/2}} \rightarrow \frac{x^3 y \sqrt{7y}}{2 \sqrt{2z}} \rightarrow \frac{x^3y \sqrt{7y*2z}}{2} \rightarrow \frac{x^3y \sqrt{14yz}}{2}\]

  21. amistre64
    • 5 years ago
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    the 4z under would be odd

  22. anonymous
    • 5 years ago
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    oh okay that makes sense :) Thank you

  23. amistre64
    • 5 years ago
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    lol.... I just got why 4z is on the bottom :) I forgot a step .....

  24. amistre64
    • 5 years ago
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    2 * sqrt(2z) * sqrt(2z) = 2*2z = 4z lol

  25. anonymous
    • 5 years ago
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    lol it's okay thanks for your help

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