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anonymous
 5 years ago
how do you simplify ln square root e, and is the answer e^2?
anonymous
 5 years ago
how do you simplify ln square root e, and is the answer e^2?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no it is \[\frac{1}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ln(x)=y\] same as \[e^y=x\] \[ln(\sqrt{e})=ln(e^{\frac{1}{2}})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is starting to make a lot more sense thanx a lot!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and since clearly \[e^{y}=e^{\frac{1}{2}}\] makes \[y=\frac{1}{2}\] we get \[ln(e^{\frac{1}{2}})=\frac{1}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this of it this way. \[ln(x)\] is the power you raise e to to get x. therefore \[ln(e^y)=y\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just like \[log_3(3^2)=2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and \[log_{10}(.001)=3\] since \[10^{3}=.001\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, since \[10^{4}=\frac{1}{10^4}=\frac{1}{10000}=.0001\]
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