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anonymous
 5 years ago
how do you solve f(x)=2^3x+5 and how do you find f^1 9x) ?
anonymous
 5 years ago
how do you solve f(x)=2^3x+5 and how do you find f^1 9x) ?

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shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Use the log, Luke ;) Seriously though, when you see a variable in a power, you can use logs to pull it out. Since you're solving, set f(x) = 0 and get: \[0 = 2^{3x} + 5\] Now try to see if you can get that into a log form that makes sense.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do i do after i get 2^3x = 5 ?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Ok, so remember: \[a^b = c\] \[log_a c = b\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Can you apply that above?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Hm... Wait... Hehehe. I have detected a problem! That requires the log of a negative number, which does not exist.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what do i do then?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Just to double check, the equation is: \[f(x)=2^{3x}+5\] Right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that it? shouldn't there be more problem solving?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Can your answer have imaginary numbers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it polly should my math teacher loves i

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Hahaha. Well, the log of 5 is 0.698970004 + 1.36437635 i :p

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Hehe. Yeah it's kind of nasty. If it were 2^(3x)  5 instead of + 5 things would be a lot better.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanx though awesome response math wizard (:

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Oh that's not me. Amistre's not here at the moment but he's the wizard around here ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, wait how is the second part done?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.1Post that as a separate question. I'm a bit rusty on function inverses :)
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