how do you solve f(x)=2^3x+5 and how do you find f^-1 9x) ?

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how do you solve f(x)=2^3x+5 and how do you find f^-1 9x) ?

Mathematics
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Use the log, Luke ;) Seriously though, when you see a variable in a power, you can use logs to pull it out. Since you're solving, set f(x) = 0 and get: \[0 = 2^{3x} + 5\] Now try to see if you can get that into a log form that makes sense.
what do i do after i get 2^3x = -5 ?
?

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Ok, so remember: \[a^b = c\] \[log_a c = b\]
Can you apply that above?
i'll try...
Hm... Wait... Hehehe. I have detected a problem! That requires the log of a negative number, which does not exist.
?
so what do i do then?
Just to double check, the equation is: \[f(x)=2^{3x}+5\] Right?
yeah
is that it? shouldn't there be more problem solving?
Can your answer have imaginary numbers?
it polly should my math teacher loves i
Hahaha. Well, the log of -5 is 0.698970004 + 1.36437635 i :p
ow and wow OK
Hehe. Yeah it's kind of nasty. If it were 2^(3x) - 5 instead of + 5 things would be a lot better.
thanx though--- awesome response math wizard (:
Oh that's not me. Amistre's not here at the moment but he's the wizard around here ;)
oh, wait how is the second part done?
f ^-1 (x)?
Post that as a separate question. I'm a bit rusty on function inverses :)
k

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