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anonymous
 5 years ago
Solve the system, using substitution.
4x + y = 4 and y = 4  4x
A. no solution
B. infinitely many solutions
I put A is this correct?
anonymous
 5 years ago
Solve the system, using substitution. 4x + y = 4 and y = 4  4x A. no solution B. infinitely many solutions I put A is this correct?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's ok, Ill answer:P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[4x+y=4\ and \ y =4x+4\] substituting y into \[4x+y=4\] gives you \[4x+(4x+4)=4\] which would end up with zero because 4x and 4x would cancel and then you would be left with 4=4
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