Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jonessodagirl73

  • 4 years ago

how do you complete the square in the equation 4y^2-2x+8y+1=0?

  • This Question is Closed
  1. 7njap
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Okay. I think I’ve got it. First off, move all your y’s to one side of the equation, and all your x’s to the other. 4y^2 + 8y = 2x – 1 Next step, you have to make 1 the coefficient of your y^2! So divide everything by 4. y^2 + 2y = 2x/4 – ¼ Now, take the coefficient of your y^2 (which we made 1), and multiply it by the coefficient of y. That gives you 1. Insert this number on both sides of the equation! y^2 + 2y + 1 = 2x/4 – ¼ + 1 Now you can make the left-hand side of the equation (y+1)^2! All you have to do now is rearrange stuff in the formula, isolating the x. 2 (y + 1)^2 – 6/4 = x I hope I haven’t made any mistakes!

  2. jonessodagirl73
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanx a million!

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy