Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jonessodagirl73 Group Title

how do you complete the square in the equation 4y^2-2x+8y+1=0?

  • 3 years ago
  • 3 years ago

  • This Question is Closed
  1. 7njap Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Okay. I think I’ve got it. First off, move all your y’s to one side of the equation, and all your x’s to the other. 4y^2 + 8y = 2x – 1 Next step, you have to make 1 the coefficient of your y^2! So divide everything by 4. y^2 + 2y = 2x/4 – ¼ Now, take the coefficient of your y^2 (which we made 1), and multiply it by the coefficient of y. That gives you 1. Insert this number on both sides of the equation! y^2 + 2y + 1 = 2x/4 – ¼ + 1 Now you can make the left-hand side of the equation (y+1)^2! All you have to do now is rearrange stuff in the formula, isolating the x. 2 (y + 1)^2 – 6/4 = x I hope I haven’t made any mistakes!

    • 3 years ago
  2. jonessodagirl73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    thanx a million!

    • 3 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.