anonymous
  • anonymous
derivative!! help!!::: y=2sinx-5cosx
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Do one term at a time.
anonymous
  • anonymous
i know for stuff like :x^3+x^2, it's just = 3x^2+2x but how would you do it one by one for SIN and COS??
anonymous
  • anonymous
derivative of sin= cos derivative of cos=-sin

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anonymous
  • anonymous
Is the first part -2cosx?
anonymous
  • anonymous
ohh, so it's just -2cosx +5sin?
anonymous
  • anonymous
You have the derivatives in my note above. Please note the signs.
anonymous
  • anonymous
aaak I subtracted should be added: f'g + g'f f=2 f'=0 g=sinx g'=cos x 0*sinx + cosx * 2 but for reasons known only to my brain I wanted to subtract so first part is 2 cosx no negativity
anonymous
  • anonymous
bad kantalope! trying to do things in head
anonymous
  • anonymous
No multiplication rule.
anonymous
  • anonymous
no? uh oh....what rule should I be usin?
anonymous
  • anonymous
Since they are added, you just find the derivative of each.
anonymous
  • anonymous
right so 2sinx is two times sine x ya? how come no multiplication rule? Ah because it is not (2x)sinx......so should treat it like coefficient in 3x^2
anonymous
  • anonymous
Right 2 is just a coefficient, it goes along for the ride, as they say.
anonymous
  • anonymous
well dang it - that explains some of my test scores lol
anonymous
  • anonymous
It takes time to sink in. You've got it now.
anonymous
  • anonymous
this is the answer 2cosx+5sinx
anonymous
  • anonymous
i hope my memory did not tell me wrong.:)lol

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