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anonymous

  • 5 years ago

the area of a triange can be modeled: A(x)=x^3-1. The length is x-1. Find a polynomial to represent the width of the triangle. (the answer is x^2 + x +1 .... how do u get that?)

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  1. anonymous
    • 5 years ago
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    Is this an equilateral triangle? or an arbitrary triangle?

  2. watchmath
    • 5 years ago
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    Notice that \(x^3-1=(x-1)(x^2+x+1)\) So the width od the triangel is \(2(x^2+x+1)\)

  3. anonymous
    • 5 years ago
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    not sure why the "2" is there. \[\frac{x^3-1}{x-1}=x^2+x+1\]

  4. watchmath
    • 5 years ago
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    I guess area of triangle is 1/2*base*height

  5. anonymous
    • 5 years ago
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    is the length and width? can we base and sides?

  6. anonymous
    • 5 years ago
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    oops you are right. how could i doubt it?

  7. anonymous
    • 5 years ago
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    OMG I MENT RECTANGLE SRY GUYS

  8. anonymous
    • 5 years ago
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    lol well i read "rectangle' too so it must have been a subliminal message. then there is no 2!

  9. anonymous
    • 5 years ago
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    x^3−1 -------- x−1 =x^2+x+1 how is that equal to that?

  10. anonymous
    • 5 years ago
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    actually, you are just going to use the formula of the area of a rectangle which is length times width A=lw \[x ^{3}-1=w(x-1)\] divide both sides by x-1 then you will get x^3−1 -------- x−1 which is equal to x^2+x+1 through factoring its gcf.

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