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do you know how to find the derivative of \[\frac{3x-2}{6-5x}\]?

that is all the hard work.

i can write it for you if you like

hello anwar. feel like writing it out?

\[{d \over dx}({3x-2 \over (6-5x)^4})={3(6-5x)-4(3x-2)(6-5x)^3(-5) \over (6-5x)^8}\]
Simplify!!

hello satellite :)

ok i will. i get \[\frac{8}{(5x-6)^2}\]

The denominator is raised to the power of 4, isn't it?

so back to the problem. the derivative will be
\[4(\text{inside thing})^3\times \frac{8}{(5x-6)^2}\]

Oh the whole thing.. my bad.

no i was assuming it was the whole thing raised to the 4th. chain rule and all that.

never mind my solution doshi, just stick with satellite :D

inside piece just \[\frac{3x-2}{5x-6}\]

Yeah.

well actually it is
\[\frac{3x-2}{6-5x}\]

whose derivative is \[\frac{3(6-5x)+5(3x-2)}{(5x-6)^2}=\frac{8}{(5x-6)^2}\]

The derivative
\[y'=4({3x-2 \over 6-5x})^3{8 \over (6-5x)^2}\]

bet we lost doshi somewhere

probably gave up in disgust

I think so :D