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anonymous

  • 5 years ago

Write a system of two equations using x and y to represent the following problem. A chemist is mixing two solutions together. The chemist wants 100 gallons when complete. He is mixing a 24% solution with a 50% solution to get a 36% solution. How many gallons of each will he use?

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  1. anonymous
    • 5 years ago
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    call the amount of 50% solution x and then the amount of 36% solution is 100-x

  2. anonymous
    • 5 years ago
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    oops let me start again. call the amount of 50% solution x and the amount of 24% solution is then 100-x

  3. anonymous
    • 5 years ago
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    so \[.5x+.24(100-x)=.36\times 100=36\]

  4. anonymous
    • 5 years ago
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    this is what you need to solve. \[.5x+24-.24x=36\] \[.26x+24=36\] \[.26x=12\] \[x=\frac{12}{.26}=46.15\] rounded

  5. anonymous
    • 5 years ago
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    but if i would read correctly it only says "wrote two equations" the first would be \[x+y=100\] and the second would be \[.5x+.24y=.6\]

  6. anonymous
    • 5 years ago
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    rather \[.5x+.24y=36\]

  7. anonymous
    • 5 years ago
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    Ah i see (:

  8. anonymous
    • 5 years ago
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    So then...

  9. anonymous
    • 5 years ago
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    it doesn't say to solve them does it?

  10. anonymous
    • 5 years ago
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    x+y = 100 .24x + .5y = .36 * 100

  11. anonymous
    • 5 years ago
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    Yea i do need to solve them. i can prolly do that on my own tho.... :P retaking assignments from the begining of the year >.< Dont remember a thing

  12. anonymous
    • 5 years ago
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    if you want to solve it a systems you have \[x+y=100\] \[.5x+.24y=36\]

  13. anonymous
    • 5 years ago
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    multiply the bottom equation by -2 and the x's will drop out

  14. anonymous
    • 5 years ago
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    \[x+y=100\] \[-x-.48y=-72\]

  15. anonymous
    • 5 years ago
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    dude, thats weird. let y = 100 - x and substitute that into the second equation,

  16. anonymous
    • 5 years ago
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    add them and the x's drop out to get one equation in y \[.52y=28\] \[y=\frac{28}{.52}=53.846\] rounded

  17. anonymous
    • 5 years ago
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    Naw he is doing elimination, thats substitution... i suck at substitution.. so go ahead and do elimination.. lol

  18. anonymous
    • 5 years ago
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    i did that first.

  19. anonymous
    • 5 years ago
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    Okay (:

  20. anonymous
    • 5 years ago
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    cantorset first line i used 100-x for y. but what is odd is that usually these problems are cooked up to give nice integer answers. this one is not.

  21. anonymous
    • 5 years ago
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    unless my arithmetic is wrong. i got two ugly decimal answer. it is 50%, 24% and 36% yes?

  22. anonymous
    • 5 years ago
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    oh ok

  23. anonymous
    • 5 years ago
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    i trust your work , but first you want to multiply both sides to remove the decimal, if youre doing elimination

  24. anonymous
    • 5 years ago
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    for the second equation, multiply both sides by 100 first

  25. anonymous
    • 5 years ago
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    you try it and see if you don't get something ugly. maybe i made a mistake. really please try it.

  26. anonymous
    • 5 years ago
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    ok

  27. anonymous
    • 5 years ago
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    still get \[x=\frac{12}{.26}=\frac{1200}{26}=46.153846...\]

  28. anonymous
    • 5 years ago
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    sat, bear with me, im tutoring 3 other people, sorry

  29. anonymous
    • 5 years ago
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    Oh yea! ^^ i think you said something about being a online tutor for money or something :P Continue though satellite (:

  30. anonymous
    • 5 years ago
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    and they COMPLAIN, lol

  31. anonymous
    • 5 years ago
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    yes real coin

  32. anonymous
    • 5 years ago
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    They people your tutoring? Haha

  33. anonymous
    • 5 years ago
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    You must be making bank.... lmfao.. kidding (:

  34. anonymous
    • 5 years ago
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    yup

  35. anonymous
    • 5 years ago
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    not really, im working like a dog

  36. anonymous
    • 5 years ago
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    Wow... i sure cant wait to get done with high school..... :P lol

  37. anonymous
    • 5 years ago
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    So i can go on to work like a dog... and make no money... sounds wonderful :P lol

  38. anonymous
    • 5 years ago
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    still get x=46.15 rounded making y = 53.85 rounded

  39. anonymous
    • 5 years ago
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    Okay (: Thanks!

  40. anonymous
    • 5 years ago
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    welcome

  41. anonymous
    • 5 years ago
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    why are you doing this and also \[b^0\] at the same time? odd

  42. anonymous
    • 5 years ago
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    Haha i am retaking stuff i learned at the begining of the year :P I seriously barely remember anything. lol

  43. anonymous
    • 5 years ago
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    good luck. it will be over soon enuf

  44. anonymous
    • 5 years ago
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    Ya i sure hope so :P At least i got this cite tho! ^^

  45. anonymous
    • 5 years ago
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    what is b^0 ?

  46. anonymous
    • 5 years ago
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    Idk how to explain it... ^_T just know im doing it :P I bet satellite can tho (:

  47. anonymous
    • 5 years ago
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    wait, he said youre "taking" b^0

  48. anonymous
    • 5 years ago
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    Haha no its just something him and i think its polpak showed me how to do.

  49. anonymous
    • 5 years ago
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    Lilly allen sucks,

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