anonymous
  • anonymous
Solve, x-(3/5) = (7/10 x minus 3 over 5 equals 7 over 10
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Multiply both sides by 10, you get: \[10x-6=7 \implies 10x=13 \implies x={13 \over 10}\]
anonymous
  • anonymous
@AnwarA Where did you get the 6 from?
anonymous
  • anonymous
\[-\frac{3}{5}\times 10=-6\]

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anonymous
  • anonymous
As satellite said.
anonymous
  • anonymous
The answer in the book says its negative 1 over 10.
anonymous
  • anonymous
I wanna know the steps to solve this equation...
anonymous
  • anonymous
is it \[x-\frac{3}{5}=\frac{7}{10}\]
anonymous
  • anonymous
or \[\frac{x-3}{5}=\frac{7}{10}\]?
anonymous
  • anonymous
yes, the first one
anonymous
  • anonymous
well then the answer in the book is wrong, because anwar is right.
anonymous
  • anonymous
one step problem if you do not mind the fractions: \[x-\frac{3}{5}=\frac{7}{10}\] add \[\frac{3}{5}\] to both sides to get \[x=\frac{7}{10}+\frac{3}{5}=\frac{7}{10}+\frac{6}{10}=\frac{13}{10}\]
anonymous
  • anonymous
No i figured it out. 3/5 is equal to 6/10 so to solve for x i have to get x alone so i minus 6/10 from both sides & 7/10 minus 6/10 equals 1/10 so that makes x=1/10
gw2011
  • gw2011
3/5 does equal 6/10 but you have to add 6/10 to both sides and not subtract it because you have a -3/5 and not a +3/5
anonymous
  • anonymous
unfortunately \[-\frac{3}{5}-\frac{3}{5}=-\frac{6}{5}\] not 0. you have to add \[\frac{3}{5}\] to both sides
anonymous
  • anonymous
scratch that, idk why it says 1/10 for the answer in the book. i'll leave that for the teacher to explain.thanks anyways :)
radar
  • radar
x-3 7 ---- =---- multiply through by 10 5 10 2(x-3) = 7 2x-6 = 7 2x=13 x=13/2

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