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anonymous

  • 5 years ago

Solve, x-(3/5) = (7/10 x minus 3 over 5 equals 7 over 10

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  1. anonymous
    • 5 years ago
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    Multiply both sides by 10, you get: \[10x-6=7 \implies 10x=13 \implies x={13 \over 10}\]

  2. anonymous
    • 5 years ago
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    @AnwarA Where did you get the 6 from?

  3. anonymous
    • 5 years ago
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    \[-\frac{3}{5}\times 10=-6\]

  4. anonymous
    • 5 years ago
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    As satellite said.

  5. anonymous
    • 5 years ago
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    The answer in the book says its negative 1 over 10.

  6. anonymous
    • 5 years ago
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    I wanna know the steps to solve this equation...

  7. anonymous
    • 5 years ago
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    is it \[x-\frac{3}{5}=\frac{7}{10}\]

  8. anonymous
    • 5 years ago
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    or \[\frac{x-3}{5}=\frac{7}{10}\]?

  9. anonymous
    • 5 years ago
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    yes, the first one

  10. anonymous
    • 5 years ago
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    well then the answer in the book is wrong, because anwar is right.

  11. anonymous
    • 5 years ago
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    one step problem if you do not mind the fractions: \[x-\frac{3}{5}=\frac{7}{10}\] add \[\frac{3}{5}\] to both sides to get \[x=\frac{7}{10}+\frac{3}{5}=\frac{7}{10}+\frac{6}{10}=\frac{13}{10}\]

  12. anonymous
    • 5 years ago
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    No i figured it out. 3/5 is equal to 6/10 so to solve for x i have to get x alone so i minus 6/10 from both sides & 7/10 minus 6/10 equals 1/10 so that makes x=1/10

  13. gw2011
    • 5 years ago
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    3/5 does equal 6/10 but you have to add 6/10 to both sides and not subtract it because you have a -3/5 and not a +3/5

  14. anonymous
    • 5 years ago
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    unfortunately \[-\frac{3}{5}-\frac{3}{5}=-\frac{6}{5}\] not 0. you have to add \[\frac{3}{5}\] to both sides

  15. anonymous
    • 5 years ago
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    scratch that, idk why it says 1/10 for the answer in the book. i'll leave that for the teacher to explain.thanks anyways :)

  16. radar
    • 5 years ago
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    x-3 7 ---- =---- multiply through by 10 5 10 2(x-3) = 7 2x-6 = 7 2x=13 x=13/2

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