Use logarithmic differentiation to find the derivative of the function: y=(5x-4)^4 (x^5-6)^7 (7x^8+9)^9

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Use logarithmic differentiation to find the derivative of the function: y=(5x-4)^4 (x^5-6)^7 (7x^8+9)^9

Mathematics
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ln y=4ln(5x-4) etc
like chguanas said. take the log. simplify using properties of the log. then take the derivative of that, then multiply by the original mess. \[4ln(5x-4)+7ln(x^5-6) +9ln(7x^8+9)\]
derivative is \[\frac{20}{5x-4}+\frac{35x^4}{x^5-6}+\frac{504x^7}{7x^8+9}\]

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so something like this: 4 * (1/(5x-4)) * 5/1
then just write that times the origial thing and you are done.
ok got it thanks you so much
yeah chain rule. derivative of \[ln(f(x))=\frac{f'(x)}{f(x)}\]
I have a final tomorrow and was really scare for that one

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