At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
none. it will be f(x+y)=f(x)f(y)
I see you stopped asking questions on coordinate geometry!
lol.^ and that is not a possible answer.
Are you sure it can't be f(x+y)=f(x)+f(y) ?
yep..it wont be tat.
observe tat a^(x+y)=(a^x)(a^y)
it's f(x+y) = f(x)f(y) example: 2^5 = 2^2 * 2^3 = 32
that's essentially what saubhik said, but with an example
so chizzle any problems?
Yes. None of these answers fit.. Wouldn't (f(x))^(y)=f(x^(y)) work?
however f(x)^y=f(xy) will work. I think u got some problems in exponents. Please clear them out instead of trying for the options :) Ask me if u hav any prob:)
What do you mean clear them out instead of trying for the options?
I mean that u can urself answer ur doubts if u had ur basics clear:) If u are uncomfortable with exponents ask me freely!
I'm fine with exponents. It's when it comes to all variables, functions, logarithms, and having to plug things in that I get confused.
If u know (2^3)*(2^1)=2^4 then u automatically know a^x*a^y=a^(x+y) Hint: If u have problems with variables or find difficult to deal with them assign a value to each variable given in the question and the also in the options.
like above u could have assigned x=1 a=2 y=2. etc.. But be careful while dealing with numbers since some numbers cant be used like taking y=1 will prove d correct while its wrong actually. So u must deal with more than 1 numbers.